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3 years ago

14

Which of the ordered pairs in the form (x, y) is a solution of this equation?

1 answer:

emmasim [6.3K]3 years ago

7 0

You check both of them:
1. 3*3-(-8)/4=9-(-2)=9+2=11 it's true
2. 3*4-4/4=12-1=11 true
so both of them are solutions

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How to find the exact answer of the area and circumference

Paha777 [63]

Answer:

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Step-by-step explanation:

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3 years ago

In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.

bezimeni [28]

Given:

In the circle, $m(\overarc{VUX})=152^\circ$ and $m(\angle MUV)=77^\circ$ .

To find:

The following measures:

(a) $m\angle VUX$

(b) $m\angle UXW$

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

$m(VUX)=2\times m\angle VWX$

$152^\circ=2\times m\angle VWX$

$\dfrac{152^\circ}{2}=m\angle VWX$

$76^\circ=m\angle VWX$

In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

$m\angle VUX+m\angle VWX=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle VUX+76^\circ=180^\circ$

$m\angle VUX=180^\circ-76^\circ$

$m\angle VUX=104^\circ$

Now,

$m\angle UXW+m\angle UVW=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle UXW+77^\circ =180^\circ$

$m\angle UXW=180^\circ-77^\circ$

$m\angle UXW=103^\circ$

Therefore, $m\angle VUX=104^\circ$ and $m\angle UXW=103^\circ$ .

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3 years ago

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3 years ago

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torisob [31]

Answer:

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Step-by-step explanation:

2+4+6+8 = 20

20 / 4 = 5

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3 years ago

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Sladkaya [172]

Answer:

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3 years ago