All categories

3 years ago

Write 4.630 in word form

Mathematics

2 answers:

Ivahew [28]3 years ago

4 0

Four and six hundred thirty thousandths
or four and sixty-three hundredths

melamori03 [73]3 years ago

3 0

Four point six three zero.

You might be interested in

Find a ratio equivalent to 15/60

Flauer [41]

Answer:

$\large\boxed{\dfrac{15}{60}=\dfrac{5}{20}=\dfrac{3}{12}=\dfrac{1}{4}}$

$\large\boxed{\dfrac{15}{60}=\dfrac{30}{120}=\dfrac{45}{180}=\dfrac{60}{240}}$

Step-by-step explanation:

Divide the numerator and the denominator by the same number:

$\dfrac{15}{60}\\\\=\dfrac{15:5}{60:5}=\dfrac{3}{12}\\\\=\dfrac{15:3}{60:3}=\dfrac{5}{20}\\\\=\dfrac{15:15}{60:15}=\dfrac{1}{4}\\\vdots$

Multiply the numerator and the denominator by the same number:

$\dfrac{15}{60}\\\\=\dfrac{15\cdot2}{60\cdot2}=\dfrac{30}{120}\\\\=\dfrac{15\cdot3}{60\cdot3}=\dfrac{45}{180}\\\\=\dfrac{15\cdot4}{60\cdot4}=\dfrac{60}{240}\\\vdots$

7 0

3 years ago

Read 2 more answers

Find f(-7) when f(x)=- 29/x-4

vladimir1956 [14]

Answer:

f(-)=29/11

Step-by-step explanation:

Even though you don't want an explanation, I'll just tell you the basics lol.

So what you have to do, is plug in -7 for the x's.

it should look something like the equation below.

$f\left(-7\right)=\frac{-29}{-7-4}$

After that all you need to is just to subtract :)

$f\left(-7\right)=\frac{-29}{-11}$

Then after that all you need to do is just let the negatives cancel out each other so you should get:

$f\left(-7\right)=\frac{29}{11}$

Hope this helps!

5 0

3 years ago

Answer correct you get brainliest answer

zloy xaker [14]

Answer:

$y = {x}^{2} - 2$

Or if you want with the value of h too.

$y = {(x - 0)}^{2} - 2$

Step-by-step explanation:

$y = a {(x - h)}^{2} + k$

Find the value of h and k by using the formula.

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

From y = x²-2

$a = 1 \\ b = 0 \\ c = - 2$

Substitute these values in the formula.

$h = - \frac{0}{2(1)} \\ h = 0$

Therefore, h = 0.

$k = \frac{4(1)( - 2) - {0}^{2} }{4(1)} \\ k = \frac{ - 8}{4} \\ k = - 2$

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

$y = a {(x - h)}^{2} + k \\ y = 1 {(x - 0)}^{2} - 2 \\ y = {(x)}^{2} - 2 \\ y = {x}^{2} - 2$

These type of equation where b = 0 can also be both standard and vertex form.

4 0

3 years ago

The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$

d) $t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)$

$N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h$

6 0

3 years ago

Can u someone help me ? Plz

NARA [144]

What is the question?

6 0

4 years ago