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1 year ago

Can someone please sovle this

Mathematics

1 answer:

IrinaVladis [17]1 year ago

3 0

Answer:

sure. x=12

Step-by-step explanation:

firstly! we know that the two sections equal 90 degrees (because a right angle is 90 degrees). so, take both of those sections, and put them equal to 90 in an equation.

it would look like this...

(x+42) + (3x) = 90

which is the same as...

<u>x + 42</u> + <u>3x</u> = 90. ignore the parenthesis. they're just for clarification. then we will solve for x!

add similar things together! see x and 3x? those are similar because they have x in them. (HOWEVER! if it's something like x² and x, do not add them together!) x is the same as 1x, by the way. so 1x + 3x. ignore the Xs and add the numbers. it becomes 4x

4x + 42 = 90

move 42 to the other side by minusing it on both parts of the equation!

4x = 90 - 42

4x = 48

divide 48 by 4 so x is alone. there ya go

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Answer:

about 2949 feet

Step-by-step explanation:

The geometry of the situation can be modeled by a right triangle. The height of the cliff can be taken to be the side opposite the given angle, and the distance to the coyote will be the side adjacent to the given angle. The relation between these values is the trig function ...

Tan = Opposite/Adjacent

<h3>setup</h3>

Filling in the known values, we have ...

tan(6°) = (310 ft)/(distance to coyote)

<h3>solution</h3>

Multiplying by (distance to coyote)/tan(6°) gives ...

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2 years ago

A new gas- and electric-powered hybrid car has recently hit the market. The distance traveled on 1 gallon of fuel is normally di

Doss [256]

Answer:

a) P [ Z > 70 ] = 0.1075 or 10.75 %

b) P [ Z < 60 ] = 0.1038 or 10.38 %

c) P [ 55 ≤ Z ≤ 70 ] = 0.8882 or 88.82 %

Step-by-step explanation:

Normal Distribution μ = 65 and σ = 4

a) The probability of the car travels more than 70 miles per gallon is:

P [ Z > 70 ] = (Z-μ) ÷ σ ⇒ P [ Z > 70 ] = (70-65) ÷4 P [ Z > 70 ] = 1.25

the point 1.25 corresponds at values, from left tail up to 70 so we must go and look for the area for the point 1.24 which is 0.8925. Then we have the area or probability of all cars traveling up to 70 miles therefore we have to subtract 1 -0,8925

P [ Z > 70 ] = 0.1075 or 10.75 %

b)The probability of the car travels less than 60 miles per gallon is:

P [ Z < 60 ] = ( 60 - μ ) ÷ σ ⇒ P [ Z < 60 ] = (60-65)÷ 4 P [ Z < 60 ] = -1.25

Again -1.25 corresponds to 60 miles per gallon threfore we move to the left and find for point -1.26 which area is 0.1038 so

P [ Z < 60 ] = 0.1038 10.38 %

c) P [ 55 ≤ Z ≤ 70]

For point Z = 70 or 1.25 (case a above) P [ Z ≤ 70] = (70-65)÷4

P [ Z ≤ 70] = 1.25

In this case we got the whole area from the left tail up to 1.25

P [ Z ≤ 70] = 0.8944 (includes the area of the point from the left tail up to the point assocciated to 55 miles and for that reason we have to subtract that area)

P [ Z ≥ 55 ] = (55-65) ÷ 4 P [ Z ≥ 55 ] = -2.5 and the area is 0.0062

So P [ 55 ≤ Z ≤ 70 ] = 0.8944 - 0.0062 = 0.8882

8 0

4 years ago