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vodomira [7]
3 years ago
8

HELPP!!

Mathematics
2 answers:
zalisa [80]3 years ago
5 0
I think it is c because it is going up
Tresset [83]3 years ago
3 0
I would say it’s C and B
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Look at the following sequence.
expeople1 [14]

Answer:

r \:  =  \:   \boxed{ \bold{\frac{2}{3} }}

Step-by-step explanation:

  • Calculate the ratio of the progression by dividing a term of it by the immediately preceding one.

r \:  =  \:  \frac{36}{54}  \\  \\ r \:  =  \:  \frac{24}{36}  \\  \\ r \:  =  \:  \frac{16}{24}

  • We simplify the fractions:

r \:  =  \:  \frac{2}{3}  \\  \\ r \:  =  \:  \frac{2}{3}  \\  \\ r \:  =  \:  \frac{2}{3}

Since the ratio is the same, that is the common ratio.

<h3><em><u>MissSpanish</u></em></h3>

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2 years ago
Last one pls help for brainlest
Marat540 [252]

Answer:

24/30-5/30=19/30

this is the answer

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3 years ago
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balu736 [363]
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4 0
3 years ago
Module 5 (part 1) Assignment - Quadratic Equations
Virty [35]
A,e,f have 2 solutions
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A CAT scan produces equally spaced cross-sectional views of a human organ that provide information about the organ otherwise obt
True [87]

Answer:

1,107 cc

Step-by-step explanation:

The 10 intervals of the scanning are

[0,1.5), [1.5,3), [3,4.5), [4.5,6), [6,7.5), [7.5,9), [9,10.5), [10.5,12), [12,13.5), [13.5,15)

The ideal thing would be to estimate the volume with the Midpoint Rule should be take n=10.

As we must use n=5, we divide the interval [0,15] in five intervals of length 15/5 = 3

[0,3], [3,6], [6,9], [9,12], [12,15] and take their midpoints

1.5, 4.5, 7.5, 10.5, and 13.5.

Now we estimate the volume V of 5 cylinders of height h=3 and area of the base A equals to the area given for the scanning where that midpoints fall

Cylinder 1

Midpoint=1.5, interval of scanning 2nd

A = 18, V= height*area of the base = 18*3 =54  cc

Cylinder 2

Midpoint=4.5, interval of scanning 4th

A = 78, V= height*area of the base = 78*3 =234  cc

Cylinder 3

Midpoint=7.5, interval of scanning 6th

A = 106, V= height*area of the base = 106*3 =318  cc

Cylinder 4

Midpoint=10.5, interval of scanning 8th

A = 129, V= height*area of the base = 129*3 =387  cc

Cylinder 5

Midpoint=13.5, interval of scanning 10th

A = 38, V= height*area of the base = 38*3 =114  cc

And the <em>estimate volume </em>is

54+234+318+387+114=1,107 cm^3

6 0
3 years ago
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