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SashulF [63]
3 years ago
9

A ladder is leaning against the side of a building. The building and the ground form a right angle. How high on the

Mathematics
2 answers:
satela [25.4K]3 years ago
8 0

Answer:

15m

Step-by-step explanation:

(see attached)

Whitepunk [10]3 years ago
8 0
C. 15 respectfully no other answer
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WILL MARK BRAINLEIST!! Each figure is composed of large squares and small squares. The side length of the
julsineya [31]

9514 1404 393

Answer:

  A. x² -4

  B. 2x² +8

Step-by-step explanation:

The area of a square is the square of the side lengths. That means the area of each large square is x², since it has a side length of x.

__

A. The area of 4 small squares is subtracted from the area of the large square to find the shaded area:

  x² -4×1² = x² -4 . . . area of Figure A

__

B. The area of two small squares is added to the area of two large squares to find the shaded area:

  2x² +2×2² = 2x² +8 . . . area of Figure B

5 0
3 years ago
Instructions: Find the missing side of the triangle.<br> 48<br> 50
Lynna [10]

Answer:

x = 14

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

48 ^2 + x^2 = 50^2

2304+x^2=2500

x^2 = 2500-2304

x^2 =196

Taking the square root of each side

sqrt(x^2) = sqrt(196)

x = 14

4 0
3 years ago
Read 2 more answers
What’s the soccer field answer to 120 yards long and 369 so do we subtract or multiply or divide
balandron [24]

Answer:

it is 17 %5#5%×55!:5=5×555!:4÷55x5xx5x5x5x5x5x5 = 2000

8 0
3 years ago
Which shows 63 factored into powers of prime numbers?   A. 9 • 7   B. 32 • 7   C. 33 • 7   D. 3 • 3 • 7
s2008m [1.1K]

Hi!

<h3>To find the prime factorization of a number, keep dividing by the smallest factor that goes into it. </h3>

63/3 = 21

21/3 = 7

7/7 = 1

<u>3 · 3 · 7 = 63</u>

<h2>The answer is D. 3 · 3 · 7 </h2>

Hope this helps! :)

-Peredhel

6 0
3 years ago
Read 2 more answers
22. Determine the value of c so that the line
tiny-mole [99]

Answer:

If the lines BC and DE are parallel, the value of c is c=-2

Step-by-step explanation:

We are given line segment BC with end points B(2, 2) and C(9,6) and line segment DE with endpoints  D(c, -7) and E(5, -3).

Using slope formula: Slope=\frac{y_2-y_1}{x_2-x_1} we can find point c

When 2 lines are parallel there slope is same.

So, Slope of line BC =Slope of Line DE

\frac{y_2-y_1}{x_2-x_1}=\frac{y_2-y_1}{x_2-x_1}

We have:

x_1=2, y_1=2, x_2=9, y_2=6 \ for \ line \ BC \ and \\\x_1=c, y_1=-7, x_2=5, y_2=-3 \ for \ line \ DE \

Putting values and finding c

\frac{6-2}{9-2}=\frac{-3-(-7)}{5-c}\\ \frac{4}{7}=\frac{-3+7}{5-c} \\ \frac{4}{7}=\frac{4}{5-c} \\Cross \ multiply:\\4(5-c)=4*7\\20-4c=28\\-4c=28-20\\-4c=8\\c=\frac{8}{-4}\\c=-2

So, If the lines BC and DE are parallel, the value of c is c=-2

8 0
3 years ago
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