3 years ago

If the sum of $1! + 2! + 3! + \cdots + 49! + 50!$ is divided by $15$, what is the remainder?

Mathematics

1 answer:

kompoz [17]3 years ago

3 0

Answer:

Step-by-step explanation:

All factorials 5 and above are evenly divisible by 15, so have no remainder. Thus, you are interested in ...

mod(1! +2! +3! +4!, 15) = mod(1 +2 +6 +24, 15)

= mod(33, 15) = 3

The remainder is 3.

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