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Kryger [21]
3 years ago
14

Identify the first step in solving the equation below. 2003-05-04-00-00_files/i0420000.jpg A. Subtract 2w from each side. B. Mul

tiply each side by w. C. Add 2w to each side. D. Divide each side by 2.
Mathematics
2 answers:
DanielleElmas [232]3 years ago
8 0
Could you rewrite the question please  thanks
inysia [295]3 years ago
4 0
Hi!
The answer to your problem is A)0.0310 and D)1.01
A significant figure is any number that is not a stand-alone zero which means any zero in the middle of a sequence of numbers or at the end of a sequence of numbers is counted as significant, for example:           these zeros are significant (1, 2, 3, and 4 is significant as well)                |  |0000123004 |  | | |these zeros are nonsignificant

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What is the area of the sector shown in the diagram below?
Step2247 [10]
The formula to find the area of a sector = Ф*r²/2

Ф to be in radian, here Ф=45° =π/4

sector = 1/2(π/4)x 100
sector = 39.27 ≈39.3° (B)

6 0
3 years ago
If Rich decides to make no payments during the 4.5 years, the interest will be capitalized at the end of that period. a. what wi
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Step-by-step explanation:

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3 years ago
In ΔWXY, the measure of ∠Y=90°, XW = 89, WY = 80, and YX = 39. What ratio represents the cosine of ∠X?
BartSMP [9]

Answer:

It's 39/89

Step-by-step explanation:

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6 0
2 years ago
17.83 rounded to the nearest tenth
garri49 [273]
The answer would be 17.8  hope this help you

4 0
3 years ago
Find the vertices and foci of the hyperbola with equation quantity x plus 4 squared divided by 9 minus the quantity of y minus 5
My name is Ann [436]

Answer:

Vertices at (-7, 5) and (-1, 5).

Foci at (-9, 5) and (1,5).

Step-by-step explanation:

(x + 4)²/9 - (y - 5)²/16 = 1

The standard form for the equation of a hyperbola with centre (h, k) is

(x - h²)/a² - (y - k)²/b² = 1

Your hyperbola opens left/right, because it is of the form x - y.

Comparing terms, we find that

h = -4, k = 5, a = 3, y = 4

In the general equation, the coordinates of the vertices are at (h ± a, k).

Thus, the vertices of your parabola are at (-7, 5) and (-1, 5).

The foci are at a distance c from the centre, with coordinates (h ± c, k), where c² = a² + b².

c² = 9 + 16 = 25, so c = 5.

The coordinates of the foci are (-9, 5) and (1, 5).

The Figure below shows the graph of the hyperbola with its vertices and foci.

6 0
3 years ago
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