Answer:
Y'=3xy-3x-12
Y'=F(-2,-1)=0
Step-by-step explanation:
The function of the equation at the point (-2,-1)
is where the equation make the function go to zero:
Y'=3xy-3x-12
Y'=F(-2,-1)=[3(-2)(-1)]-[3(-1)]-12
F(-2,-1)=[6]-[-6]-12
F(-2,-1)=6+6-12
F(-2,-1)=12-12
F(-2,-1)=0
Solving for y
3xy-3x-12=0
y=4/x+x
Making y=0
So the values make the function go to zero
Answer:
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1/3x -11 = 4+x is what we start with, then add 11 to both sides, then subtract x from both sides. Then when we divide both sides by -2/3, x will equal -22.5.
The answer is a 12% increase.
For the first one EF is 119 degrees now since that's made with two radii it makes a central angle so whatever that arc is the central angle will be the same. fro the second one since SRQ is 52 degrees you just take that and subtract it from 180 to get SQ. I'm not quite sure about the third one. the forth you are taking the measurement of the arc its connected to and dividing that by 2 so it would be 71 degrees. I'm pretty sure in right.
