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Harman [31]
3 years ago
7

Someone please help me. It’s due in 10 minutes

Mathematics
1 answer:
storchak [24]3 years ago
7 0
This is kind of hard, good luck

リOu尺 w乇レcOʍ乇 んOア乇 ノイ ん乇レア丂
You might be interested in
Two angles of a quadrilateral measure 200° and 50°. The other two angles are in a ratio of 4:7. What are the measures of those t
Andrews [41]

Answer:

all angles will be 200, 50 , 40 and 70 - hope this helped :)

Step-by-step explanation:

everything equals to 360 after added together

360 - 250 = 110

110 divided by 11 = 10

4:7 (x 10)

40:70

the other angels will be 40 and 70

6 0
3 years ago
HELP PLZ!!!!
posledela

First, you should multiply what's inside the parenthesis.


( 6 × 3 )x + 4 + 2x


18x + 4 + 2x


Then you add the numbers that include a variable.


18x + 4 + 2x


20x + 4


The equation can not be simplified any farther, so this is our final answer.


20x + 4



- Marlon Nunez

3 0
4 years ago
The vertices of Quadrilateral ABCD are located at (1, 4), (5, 0), (2, –3), and (–2, –2).
forsale [732]

Answer:

A - Rectangle B - Square

C - Parallelogram D - Rhombus

Explanation:

We are given

A

(

1

,

2

)

,

B

(

2

,

−

2

)

and hence

A

B

=

√

(

2

−

1

)

2

+

(

−

2

−

2

)

2

=

√

17

. Further slope of

A

B

is

−

2

−

2

2

−

1

=

−

4

1

=

−

4

.

Case A -

C

(

−

6

,

−

4

)

,

D

(

−

7

,

0

)

As

C

D

=

√

(

−

7

−

(

−

6

)

)

2

+

(

0

−

(

−

4

)

)

2

=

√

17

and slope of

C

D

is

0

−

(

−

4

)

−

7

−

(

−

6

)

=

4

−

1

=

−

4

As

A

B

=

C

D

and

A

B

||

C

D

slopes being equal, ABCD is a parallelogram.

graph{((x-1)^2+(y-2)^2-0.08)((x-2)^2+(y+2)^2-0.08)((x+6)^2+(y+4)^2-0.08)((x+7)^2+y^2-0.08)=0 [-10, 10, -5, 5]}

Case B -

C

(

6

,

−

1

)

,

D

(

5

,

3

)

As

C

D

=

√

(

5

−

6

)

2

+

(

3

−

(

−

1

)

)

2

=

√

17

and slope of

C

D

is

0

−

(

−

4

)

−

7

−

(

−

6

)

=

4

−

1

=

−

4

Further,

B

C

=

√

(

6

−

2

)

2

+

(

−

1

−

(

−

2

)

)

2

=

√

17

and slope of

B

C

is

−

1

−

(

−

2

)

6

−

2

=

1

4

As

B

C

=

A

B

and they are perpendicular (as product of slopes is

−

1

), ABCD is a square.

graph{((x-1)^2+(y-2)^2-0.08)((x-2)^2+(y+2)^2-0.08)((x-6)^2+(y+1)^2-0.08)((x-5)^2+(y-3)^2-0.08)=0 [-10, 10, -5, 5]}

Case C -

C

(

−

1

,

−

4

)

,

D

(

−

2

,

0

)

As mid point of

A

C

is

(

1

−

1

2

,

2

−

4

2

)

i.e.

(

0

,

−

1

)

and midpoint of

B

D

is

(

2

−

2

2

,

−

2

+

0

2

i.e.

(

0

,

−

1

)

i.e. midpoints of

A

C

and

B

D

are same,

but,

B

C

=

√

(

2

−

(

−

1

)

)

2

+

(

−

2

−

(

−

4

)

)

2

=

√

13

i.e.

A

B

≠

B

C

and hence ABCD is a parallelogram.

graph{((x-1)^2+(y-2)^2-0.08)((x-2)^2+(y+2)^2-0.08)((x+1)^2+(y+4)^2-0.08)((x+2)^2+y^2-0.08)=0 [-10, 10, -5, 5]}

Case D -

C

(

1

,

−

6

)

,

D

(

0

,

−

2

)

As mid point of

A

C

is

(

1

+

1

2

,

2

−

6

2

)

i.e.

(

1

,

−

2

)

and midpoint of

B

D

is

(

2

+

0

2

,

−

2

+

(

−

2

)

2

i.e.

(

1

,

−

2

)

i.e. midpoints of

A

C

and

B

D

are same,

and,

B

C

=

√

(

2

−

1

)

2

+

(

−

2

−

(

−

6

)

)

2

=

√

17

i.e.

A

B

=

B

C

and hence ABCD is a rhombus.

graph{((x-1)^2+(y-2)^2-0.08)((x-2)^2+(y+2)^2-0.08)((x-1)^2+(y+6)^2-0.08)(x^2+(y+2)^2-0.08)=0 [-14, 14, -7, 7]}

3 0
3 years ago
What is 27 to the 19th power
r-ruslan [8.4K]

9514 1404 393

Answer:

  about 1.57×10^27 (see below for the exact value)

Step-by-step explanation:

  1,570,042,899,082,081,611,640,534,563  

__

Most calculators do not carry enough internal digits to compute the exact value of this number. Fortunately, there are "infinite precision" math packages around that will find this value for you.

7 0
3 years ago
A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successi
My name is Ann [436]

Answer:

option C

c. least: $101

greatest: $1001

Step-by-step explanation:

A radio station advertises a contest with ten cash prizes totaling $5510. There is to be a $100 difference between each successive prize.

Sum of 10 prizes = 5510

100 is the difference. there is a common difference d=100

So its a arithmetic sequence

the sum formula for arithmetic sequence is

S_n = \frac{n}{2}(2a_1 +(n-1)d)

Sn = 5510, n=10 n d= 100 we need to find out first term a1

5510 = \frac{10}{2}(2a_1 +(10-1)100)

5510 = 5 (2a1 + 900)

5510 = 10a1 + 4500

Subtract 4500 on both sides

1010= 10a1

divide by 10 on both sides

a1 = 101

so first term that is least term is 101

To find out greatest term we use formula

a_n = a_1 + (n-1) d

a(10) = 101 + (10-1)100

= 101 + 900= 1001

greatest is 1001

4 0
4 years ago
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