The volume of HCl gas required to prepare the solution is 101.54 L
<h3>How to determine the mole of HCl </h3>
- Volume of solution = 1.25 L
- Molarity = 3.20 M
- Mole of HCl =?
Mole = Molarity x Volume
Mole of HCl = 3.2 × 1.25
Mole of HCl = 4 moles
<h3>How to determine the volume of HCl </h3>
- Number of mole (n) = 4 moles
- Temperature (T) = 30 °C = 30 + 273 = 303 K
- Pressure (P) = 745 torr = 745 / 760 = 0.98 atm
- Gas constant (R) = 0.0821 atm.L/Kmol
Using the ideal gas equation, the volume of the HCl gas can be obtained as follow:
PV = nRT
Divide both side by P
V = nRT / P
V = (4 × 0.0821 × 303) / 0.98
V = 101.54 L
Learn more about ideal gas equation:
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Answer:
18 + 81 = 9(x² + 6x + 9) 11 = (x + 3)²
Explanation:
because This is the value that completes the square. However, since the entire square is multiplied by 9, this value must be multiplied by 9 before we can add it across the equals:
18 + 9 (9) = 9 (x² + 6x + 9)
18 + 81 = 9 (x² + 6x + 9)
99 = 9 (x² + 6x + 9)
Dividing both sides by 9, we have:
11 = x² + 6x + 9
11 = (x + 3) ²
Answer:
Solving for the Percent by Volume
The v/v concentration of acetic acid in the stop bath is 24.6%.
Explanation:
To answer the question, we need to identify certain information stated in the question. Let us write down what’s given:
Volume of solute = 160 mL
Volume of solution = 650 mL
Next, we need to determine what is required, in this case, the percent by volume. Now, let us look at the formula:
v/v concentration = (solute volume / volume of the solution) * 100
Solution:
Percent by Volume = (160 / 650) * 100
Percent by Volume = 0.2461538461538462 * 100
Percent by Volume = 24.61538461538462
Rounded off = 24.6%
Therefore, the final answer is 24.6%
Explanation:
