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kodGreya [7K]
3 years ago
12

If S is the set of positive integers that are multiples of 7, and if T is the set of positive integers that are multiple of 13,

how many integers are in the intersection of S and T?
(A) None

(B) One

(C) Seven

(D) Thirteen

(E) More than thirteen
SAT
2 answers:
ZanzabumX [31]3 years ago
6 0

Answer:

Option E

Explanation:

If We take the intersection of S and T, 91 elements will be in it i.e. 91 (Because If we multiply 7 and 13 we get 91)

Shkiper50 [21]3 years ago
5 0

Answer:

E. More than thirteen

Explanation:

S is the set of multiples of 7, meaning 7, 14, 21, 28 and so on to infinity

T is the same but with 13 instead

Both sets are infinite.

The first intersection would be 7x13 (91)

Though it would be difficult to find 14 of them to prove it, we don't have to since we know both sets are infinite and will eventually have intersections the higher they go

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Answer:

Rotation Speed = 7200 rpm

No. of tracks on one side of platter = 30000

No. of sectors per track = 600

Seek time for every 100 track traversed = 1 ms

To find:

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Explanation:

a) As given, the disk head starts at track O. At this point the seek time is 0.

Seek time is time to traverse from 0 to 29999 tracks (it makes 30000)

Average Seek Time is the time taken by the head

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b) The rotations per minute are 7200

1 min = 60 sec

7200 / 60 = 120 rotations / sec

Rotational delay is the inverses of this. So 1/120 = 0.00833 sec

= 0.00833 * 100

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Average Rotational latency is one half the amount of time taken by disk to make one revolution or complete 1 rotation.

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8.333/2 = 4.165 ms

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8.333 / 600 = 0.01388 ms = 13.88 μs

d) Total average time to satisfy a request is calculated as :

Average seek time + Average rotational latency + Transfer time for a sector

= 149.99 ms + 4.165 ms + 0.01388 ms

= 154.168 ms

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