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kodGreya [7K]
3 years ago
12

If S is the set of positive integers that are multiples of 7, and if T is the set of positive integers that are multiple of 13,

how many integers are in the intersection of S and T?
(A) None

(B) One

(C) Seven

(D) Thirteen

(E) More than thirteen
SAT
2 answers:
ZanzabumX [31]3 years ago
6 0

Answer:

Option E

Explanation:

If We take the intersection of S and T, 91 elements will be in it i.e. 91 (Because If we multiply 7 and 13 we get 91)

Shkiper50 [21]3 years ago
5 0

Answer:

E. More than thirteen

Explanation:

S is the set of multiples of 7, meaning 7, 14, 21, 28 and so on to infinity

T is the same but with 13 instead

Both sets are infinite.

The first intersection would be 7x13 (91)

Though it would be difficult to find 14 of them to prove it, we don't have to since we know both sets are infinite and will eventually have intersections the higher they go

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If (93 × p) + 84 = 8593 times p plus 84 equals 85, then p equals:.
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The solutions of  (93 × p) + 84 = 8593 times p plus 84 equals 85 yields  p =  84/8500 or 1/8593.

We can write the equation as follows;

(93 × p) + 84 = (8593  × p) + 84 = 85

We can solve the equation in parts as follows;

(93 × p) + 84 = (8593  × p) + 84

93p + 84 = 8593p

93p - 8593p = -84

-8500p = -84

p = 84/8500

Also;

(8593  × p) + 84 = 85

8593p + 84 = 85

p = 85 - 84/8593

p = 1/8593

Hence p = 84/8500 or 1/8593

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