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saveliy_v [14]
3 years ago
12

Plz help

Mathematics
1 answer:
mixas84 [53]3 years ago
7 0

x2y + z = 9 \\  \\ 1. \: x + 2y + z +  - 2y = 9 +  - 2y \\ x + z =  - 2y + 9 \\ 2. \: x + z +  - z =  - 2y + 9 +  - z \\ x =  - 2y - z + 9 \\  \\  \\ x + y - z = 5 \\  \\ 1. \: x + y - z +  - y = 5 +  - y \\ x - z =  - y + 5 \\ 2. \: x - z + z =  - y + 5 + z \\ x =  - y + z + 5 \\  \\  \\ 3x - y + 2z = 12 \\ 1. \: 3x - y + 2z + y = 12 + y \\ 3x + 2z = y + 12 \\ 2. \: 3x = y - 2z + 12 \\ 3. \:  \frac{3x}{3}  =  \frac{y - 2z + 12}{3}  \\ x =  \frac{1}{3} y +  \frac{ - 2}{3} z + 4

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In the diagram, what is the measure of angle 1?
VLD [36.1K]
We know that
 angle (3x) and angle (9x) are supplementary angles
so
3x+9x=180°------> 12x=180°------> x=180°/12-----> x=15°

angle (9x) and angle (1) are supplementary angles
so
9x+∡1=180---------> 9*15+∡1=180
∡1=180-9*15---------> ∡1=180-135------> ∡1=45°

the answer is
∡1 is 45°

alternative method
angle 1 = angle 3x----------> vertical angles
∡1=3x-----> 3*15-----> 45°
7 0
3 years ago
I’m lost again can somebody help asap ??
serious [3.7K]
Fully detailed and equipped information process right below. The answer for this question is "25" (simplified form).

\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(5^{- 5} \times 2^8 \times 1 \Bigg)^{- 2}}

\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(2^8 \times 1 \times \dfrac{1}{5^5} \Bigg)^{- 2}}

\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{2^8 \times 1}{5^5} \Bigg)^{- 2}}

\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{256}{3125} \Bigg)^{- 2}}

\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(\dfrac{3125}{256} \Bigg)^2}

\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \dfrac{3125^2}{256^2}}

\mathbf{2^{28} \times \Bigg(\dfrac{1}{2^3 \times 5^2} \Bigg)^4 \times \dfrac{3125^2}{256^2}}

\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(2^3 \times 5^2)^4} \Bigg) \times \dfrac{3125^2}{256^2}}

\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(5^2)^4 \times (2^3)^4} \Bigg) \times \dfrac{3125^2}{256^2}}

\mathbf{2^{28} \times \dfrac{1}{2^{12} \times 5^8} \times \dfrac{3125^2}{256^2}}

\mathbf{\dfrac{3125^2 \times 1 \times 2^{28}}{256^2 \times 5^8 \times 2^{12}}}

\mathbf{\dfrac{2^{(28 - 12)} \times 3125^2}{256^2 \times 5^8}}

\mathbf{\dfrac{2^{16} \times 3125^2}{256^2 \times 5^8}}

\mathbf{\dfrac{2^{16} \times (5^5)^2}{(2^8)^2 \times 5^8}}

\mathbf{\dfrac{2^{16} \times 5^{10}}{2^{16} \times 5^8}}

\mathbf{\dfrac{2^{16} \times 5^{10 - 8}}{2^{16}}}

\mathbf{\dfrac{5^{10 - 8}}{1}}

\mathbf{\therefore \quad 5^2}

\mathbf{\therefore \quad 25}

\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is: \: 25}}}

Hope it helps.
7 0
3 years ago
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damaskus [11]

Total Outcome = 6

Number greater than 4 = 2 (5&6)

So, probability would be 2/6 = 1/3

(D)OPTION D IS YOUR ANSWER

4 0
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I need some help please
Vesnalui [34]

Answer:

Choice D

Step-by-step explanation:

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Answer:

14r

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