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Lyrx [107]
2 years ago
5

Angie bought a shirt that was priced at 16.50.She paid 18.82 at the counter . what is the tax rate. Step by step

Mathematics
1 answer:
erastovalidia [21]2 years ago
6 0

Answer:

The price: 16.5

The total payment: 18.82

=> The amount of tax: 18.82-16.5 = 2.32

=> Tax rate = The amount of tax / The price = 2.32/16.5 = 0.14 = 14%

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Last time, one out of every 4 students in our class was absent. This time, after Jen came back, only one out of every 5 students
VMariaS [17]

Answer: There are 20 students and 4 students are not here today.

Step-by-step explanation:

If the number of students = 4

Let the number of students be 'x'.

Fraction of students absent = \dfrac{x}{4}

If the number of students = 5

Fraction of students absent = \dfrac{x}{5}

And Jen came back,

So, the fraction of student absent is also written as

\dfrac{x}{4}-1

According to question, it becomes,

\dfrac{x}{5}=\dfrac{x}{4}-1\\\\\dfrac{x}{5}=\dfrac{x-4}{4}\\\\4x=5(x-4)\\\\4x=5x-20\\\\4x-5x=-20\\\\-x=-20\\\\x=20

Hence, there are 20 students in our school.

And number of students are not here today is \dfrac{20}{5}=4

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3 years ago
Evaluate: 3 *-2 is an exponent, will give brainliest
natita [175]
So i dont get your question. do you need to find out what 3x10^-2 is? 
6 0
3 years ago
Review: Angle Bisectors
zmey [24]

Answer:

  • m∠AOC = 15°
  • m∠BOC = 15°

Step-by-step explanation:

Given the angle ∠AOB

It is stated that CO is the angle bisector of ∠AOB.

Given that ∠AOB = 30°

As we know that the angle bisector bisects the angle into two equal angles.

Thus, the angle bisector CO bisects the angle ∠AOB into two equal angles, which are:

  • m∠AOC
  • m∠BOC

as

∠AOB = 30°

Thus, the two formed angles i.e m∠AOC and m∠BOC by the angle bisector would be half of the angle bisector as the angle bisector bisects the angle ∠AOB into two equal angles.

Therefore,

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7 0
3 years ago
Which of the following is not a property of a chi-square distribution?
laiz [17]

Answer:

c) Is not a property (hence (d) is not either)

Step-by-step explanation:

Remember that the chi square distribution with k degrees of freedom has this formula

\chi_k^2 = \matchal{N}_1^2 +  \matchal{N}_2^2 + ... + \, \matchal{N}_{k-1}^2 +  \matchal{N}_k^2

Where N₁ , N₂m .... N_k are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.

Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true

The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.

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3 years ago
What is the fraction 7, 14 simplest form​
goldfiish [28.3K]

Answer:

1 is to 2 is the answer. U.got that

3 0
2 years ago
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