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anyanavicka [17]
2 years ago
14

The mean (rounded to the nearest tenth if needed) of the following data set is: 110, 142, 120, 180, 151, 110, 159, 173, 173, 144

, 110
A. 142.9

B. 157.2

C. 131

D. 146.8
Mathematics
2 answers:
DIA [1.3K]2 years ago
6 0

Answer:

A

Step-by-step explanation:

Add up all of the numbers:

110+142+120+180+ 151+110+159+173+173+144+110 = 1572

Next you divide by how many number there are (there are 11 numbers)

1572 ÷ 11 = 142.9090909

142.9090909 rounded to the nearest tenth is 142.9

allochka39001 [22]2 years ago
4 0

Answer:

A.  142.9

Step-by-step explanation:

There are 11 members in the data set, therefore:

The mean = (110+142+120+180+151+110+159+173+173+144+110) / 11

= 1572/11

= 142.9.

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The length of the arc of the circle with a radius of 5.4 m and the central angle measuring 60° is 5.655 meters.

<h3>What is the Length of an Arc?</h3>

The length of an arc is given by the formula,

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where

θ is the angle, which arc creates at the centre of the circle in degree.

The length of the arc of the circle with a radius of 5.4 m and the central angle measuring 60° can be written as

\text{Length of the Arc} = 2\pi r \dfrac{\theta}{360}

                            = 2 \times \pi \times 5.4 \times \dfrac{60}{360}\\\\=5.655\rm\ m

Hence, the length of the arc of the circle with a radius of 5.4 m and the central angle measuring 60° is 5.655 meters.

Learn more about Lenght of the Arc:

brainly.com/question/1577784

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In the pulley system shown in this figure, MQ = 30 mm, NP = 10 mm, and QP = 21 mm. Find MN.
ankoles [38]
<h2>Answer:</h2>

\boxed{\overline{MN}=37.96}

<h2>Step-by-step explanation:</h2>

For a better understanding of this problem, see the figure below. Our goal is to find \overline{MN}. Since:

\angle MRS=\angle MQP=90^{\circ} \\ \\ \overline{MQ}=\overline{MR}=30mm

and \overline{MN} is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:

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Applying Pythagorean theorem again, but for triangle MQN:

\overline{MN}=\sqrt{\overline{MQ}^2+\overline{QN}^2} \\ \\ \overline{MN}=\sqrt{30^2+(\sqrt{541})^2} \\ \\ \boxed{\overline{MN}=37.96}

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