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anyanavicka [17]
3 years ago
14

The mean (rounded to the nearest tenth if needed) of the following data set is: 110, 142, 120, 180, 151, 110, 159, 173, 173, 144

, 110
A. 142.9

B. 157.2

C. 131

D. 146.8
Mathematics
2 answers:
DIA [1.3K]3 years ago
6 0

Answer:

A

Step-by-step explanation:

Add up all of the numbers:

110+142+120+180+ 151+110+159+173+173+144+110 = 1572

Next you divide by how many number there are (there are 11 numbers)

1572 ÷ 11 = 142.9090909

142.9090909 rounded to the nearest tenth is 142.9

allochka39001 [22]3 years ago
4 0

Answer:

A.  142.9

Step-by-step explanation:

There are 11 members in the data set, therefore:

The mean = (110+142+120+180+151+110+159+173+173+144+110) / 11

= 1572/11

= 142.9.

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kumpel [21]

Answer:

\large\boxed{(f\circ g)(2)=0}\\\boxed{(g\circ f)(2)=4}

Step-by-step explanation:

f:\{(0,4), (1,2), \underline{(2,0)}, (3,2), (4,4)\}\\\\g:\{\underline{(0,4)}, (1,3), \underline{(2,2)}, (3,1), (4,0)\}\\\\(f\circ g)(x)=f\bigg(g(x)\bigg)\\\\g(2)=2\qquad/from\ (2,2)/\\f\bigg(g(2)\bigg)=f(2)=0\qquad/from\ (2,0)/\\\\(g\circ f)(x)=g\bigg(f(x)\bigg)\\\\f(2)=0\qquad/from\ (2,0)/\\g\bigg(f(2)\bigg)=g(0)=4\qquad/from\ (0,4)/

7 0
3 years ago
Radium 226, which had been used for cancer treatment, decays with a half-life of 1622 years. suppose there is a 6 gram sample of
sveticcg [70]
This is a relatively simple half life calculation.
To go from 6 to 3 grams, 1622 years is required.
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3 0
3 years ago
PLEASE HELP!! will give brainliest if correct! Also plz no copied answers!
PtichkaEL [24]

Answer:

What is the question

Step-by-step explanation:

5 0
3 years ago
On Texas Avenue between University Drive and George Bush Drive, accidents occur according to a Poisson process at a rate of thre
Zarrin [17]

Answer:

(a) The probability is 0.6514

(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

P(x)=\frac{e^{-at}*(at)^{x} }{x!}

Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

P(x)=\frac{e^{-3/7}*(3/7)^{x}}{x!}

P(0)=\frac{e^{-3/7}*(3/7)^{0}}{0!}=0.6514

On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

P(x)=\frac{e^{-at}*(at)^{x} }{x!}

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}

P(0)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{0}}{0!}=0.2231

Finally, P(x≥1) is:

P(x≥1) = 1 - 0.2231 = 0.7769

3 0
3 years ago
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