Answer:
You will see the recessive trait.
Explanation:
Answer:
Oxygen Depletion
Explanation:
In addition to the eutrophication of water bodies, wastewater effluents also contribute to another process of deoxygenation. The biological (bacterial) breakdown of organic solids in the effluent also consumes dissolved oxygen – the biological oxygen demand (BOD). In addition, the degradation of chemicals in the effluent removes oxygen from the water through chemical reactions – the chemical oxygen demand (COD).
As was previously mentioned, the loss of dissolved oxygen in the water can result in serious immediate, short-term, or long-term consequences to aquatic life. Fish survival is particularly affected by low oxygen levels. Decreased disease resistance, reduced growth, altered swimming behaviour, feeding, migration, and reproduction, increased threat of predation, and even rapid death are some of the effects of low dissolved oxygen concentrations.
Low oxygen levels can also alter the kinds of species present in the ecosystem. With a change in food supply, some populations of species decrease, while others increase. Fish such as whitefish, walleye, and pike may disappear, while bottom-feeding fish such as carp may increase in number.
The correct answer for the question that is being presented above is this one: "Yes, because the observed changes in histone modifications are consistent with reduced transcription." The results shown in Figure 19.5 prove conclusively that histone modifications are causing reduced Hnf4a gene transcription because <span>the observed changes in histone modifications are consistent with reduced transcription.</span>
They would most likely also become extinct, since they require them to "Fix the nitrogen" during photosynthesis, they have a "You need me, I need you" kind of thing. One can't live without the other.
Ok, colour blindness and blood type are independently assorting traits, that means that having one does not affect having the other, the question even tells you that the traits are on different chromosomes.
<span>To answer your question we'll have to calculate the probability of both traits in the child and then multiply them together to get the overall probability of both being present in the child. </span>
<span>Let's start with blood type: there are four types of blood type: AB, A, B and O. Blood type is determined by what protein each chromosome codes for: so if one chromosome is I^A and codes for A type protein, while the other is I^B and codes for B type protein, then the overall blood type will be AB. O blood type is recessive, it doesn't code for any protein at all and is given the symbol i. </span>
<span>Since both parents are type A and their first child is type O, you know that both parents are heterozygous for blood type A, meaning that one chromosome they have is I^A and the other is type or or i. For a child to be blood type O, each parent has to give their type O chromosome to the child. There is a 1/2 chance that one parent will give the recessive O chromosome, so for both parents to give their recessive allele the probability is 1/2 * 1/2 = 1/4 </span>
<span>Colour blindness is an X-linked condition, that means that women can be carriers but not manifest the colour blindness because they have one "good" X chromosome which masks the recessive colourblindness gene on the other X. The father cannot have a colourblindness gene or else he'd be colourblind himself, since he's only got 1 X-chromosome. Because dad has healthy eyesight, any girls he has will have healthy eyesight too, since his X will always be healthy and mask the X from mom if she happens to give the recessive colourblind gene. So the probability that the girl will have normal vision is 1/1. </span>
<span>However, it is not a given that the baby born will be a girl, there's a 50/50 chance that it'll be one or the other sex, so we need to consider the probability involved with the child being a girl. this probability is 1/2. </span>
<span>So now we multiply all our probabilities together to calculate what the chances of a normal visioned, type O blood typed girl is: </span>
<span>Normal vision (1) * blood type O (1/4) * girl baby (1/2) = 1/8 </span>
<span>So your probability is 1/8! </span>
<span>Hope this helps :)</span>
