All categories

3 years ago

Evaluate the expression a^2+6ab for a= -2 and b=4

Mathematics

1 answer:

harkovskaia [24]3 years ago

7 0

Substitute the numbers for letter a and b in the equation

You might be interested in

a school has 415 third grade and 338 second graders how many more third graders are there than second graders?

Alika [10]

Answer:

There are 77 more third graders than there are second graders.

Step-by-step explanation:

You just have to subtract 338 from 415 to get your answer.

6 0

3 years ago

Read 2 more answers

Please please please help and solve this with steps, much help needed thank you :) 20 points for this!

leonid [27]

Answer:

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

$\frac{dy}{dx}y=x^3+2x-5x+3$

$\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}$

$\mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)$

1. $\mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:$

$y'\:y=x^3+2x-5x+3$

2. $\mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}$

$yy'\:=x^3-3x+3$

$N\left(y\right)\cdot y'\:=M\left(x\right)$

$N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3$

3. $\mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1$

4. $\mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}$

5. $\mathrm{Simplify}$

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

7 0

3 years ago

Read 2 more answers

Please solve <br> -(6x+7)+8=19

JulijaS [17]

-6x-7+8=19 and then add your like terms so it’s -6x+1=19 and then subtract one on both sides so it’s -6x=18 so x=-3

3 0

3 years ago

How do i simplify (3/5 - 1) / 1 2/3?

Tpy6a [65]

I hope this helps you

4 0

3 years ago

1/4(1/3k+9)=6 step 1- 1/3k=15 step 2- 1/3k=15 step 3- k=5 find Olgas mistake step 1 step 2 steps 3 Olga did not make a mistake

shtirl [24]

Answer:

Step 3 contains error.

Step-by-step explanation:

The given equation is :

$\dfrac{1}{4}(\dfrac{1}{3}k+9)=6$

Step 1.

Cross multiplying,

$(\dfrac{1}{3}k+9)=24$

Step 2.

Subtract 9 from both sides

$\dfrac{1}{3}k+9-9=24-9\\\\\dfrac{1}{3}k=15$

Step 3.

Cross multiplying

$k=15\times 3\\\\k=45$

So, there is an error in step 3. The correct answer should be 45.

3 0

3 years ago