Answer:
21
Step-by-step explanation:
Answer:
equation of the circle J with center K(-7,3) and radius 6 is=
x^2+y^2+14x-6y+22=0
Step by step explanation:
Equation of circle with given centre (h,k) and radius r is
(x-h)^2+(y-k)^2=r^2
Given centre are K(-7,3) and radius 6.
So equation of Circle=
(x- -7)^2+(y-3)^2=6^2
x^2+14x+49+y^2-6y+9=36
x^2+y^2+14x-6y+22=0 answer
Answer:
-xy^6 +2y -6
Step-by-step explanation:
(-6x^2 y^8+12xy^3-36xy^2)
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6xy^2
Divide each term by 6 in the numerator and denominator
(-6/6x^2 y^8+12/6xy^3-36/6xy^2)
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6/6xy^2
-x^2y^8 +2xy^3 -6xy^2
---------------------------------
xy^2
Divide each term by x in the numerator and denominator
-x^2/xy^8 +2x/xy^3 -6x/xy^2
---------------------------------
x/xy^2
-xy^8 +2y^3 -6y^2
---------------------------------
y^2
Divide each term by y^2 in the numerator and denominator
Remember when dividing, we subtract the exponents
-xy^8/y^2 +2y^3/y^2 -6y^2/y^2
---------------------------------
y^2 /y^2
-xy^6 +2y^1 -6
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1
-xy^6 +2y -6
Answer:
A parabola
Step-by-step explanation:
It's a quadratic equation so the graph will be a parabola.
The solutions are -2 and -7
