Question

What is the solution to the inequality below? 

Answer 1

B probably but don't take my word on it

Answer 2

1) Firstly, we are working with real numbers, so we need to garantee that:

$x \geq 0 \\ \sqrt{x} \geq \sqrt{0} \\ \sqrt{x} \geq 0$

2) Secondly, we need to look at the inequation:

$\sqrt{x} \leq 8 \\ ( \sqrt{x} )^2 \leq 8^2 \\ x \leq 64$

3) Then, the solution is given by:

$\boxed {0 \leq x \leq 64}$

Letter D