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3 years ago

Find the circumference and area of a circle with radius 7 m. Use the value 3.14 for pie, and do not round your answers

Mathematics

1 answer:

vaieri [72.5K]3 years ago

8 0

Answer:

circumference (c) = 43.96cm

Area (A) = 615.44cm²

Step-by-step explanation:

Here,

Radious (r) = 7 cm

circumference (c) = $2\pi r$

= 2×3.14×7

=43.96cm

Area (A) = $4\pi r^{2}$

= 4×3.14×7²

=12.56×49

= 615.44cm²

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Someone please help me with this

Nataly_w [17]

Answer:

$a.\ D=\dfrac{1}{5}t$

b. 20 seconds

Step-by-step explanation:

Let $D$ be the distance in miles and

$t$ be the time in seconds and

$s$ be the speed in miles/sec

Formula for Distance is given as:

$Distance = Speed \times Time\\OR\\D=st$

Given that:

Distance = 2 miles and

Time = 10 seconds

Putting the values in formula:

$2=s\times 10\\\Rightarrow s =\dfrac{1}{5} \ miles/sec$

Answer a:

Putting the value of $s$ back in the formula to find the direct variation equation for the relationship between time and distance:

$D=\dfrac{1}{5}t$

Answer b:

Using the above formula and putting $D=4\ miles$ :

$4=\dfrac{1}{5}t\\\Rightarrow t =\bold{20\ seconds}$

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3 years ago

Suppose you have a bag containing 15 red beads, 12 white beads and 8 black beads. You are going to draw one bead out of the bag.

iren [92.7K]

Answer:

probability that you draw a black bead or a white bead that is P(E1 U E2)

= 20/35 = 0.571

Step-by-step explanation:

Given a bag containing 15 red beads, 12 white beads and 8 black beads

n(S) = 15 + 12 +8 = 35

Let 'E1 be the event of selecting black beads and E2 be the event of selecting white beads

n(E1) = 8 and n(E2) = 12

Probability of draw a black bead P( E1 ) = $\frac{n(E_{1} )}{n(S)}$

$P(E_{1}) = \frac{8}{35}$

Probability of draw a white bead P( E2 ) = $\frac{n(E_{2} )}{n(S)}$

$P(E_{2}) = \frac{12}{35}$

probability that you draw a black bead or a white bead that is P(E1 U E2)

and E1 n E2 = ∅ (disjoint events)

Axiom of union

$P(E_{1}UE_{2} ) = P(E_{1})+P(E_{2}) - P(E_{1}nE_{2})\\$

E1 n E2 = ∅ ⇒ P(E1 n E2) = p(∅) = 0

$P(E_{1}UE_{2} ) = P(E_{1})+P(E_{2}) - 0$

$P(E_{1}UE_{2} ) = \frac{8}{35} +\frac{12}{35}$

$P(E_{1}UE_{2} ) = \frac{20}{35}$

$P(E_{1}UE_{2} ) = 0.571$

8 0

4 years ago

The orbit of the space is approximatly a circle with a radius of 4100 mi. How far do the astronauts travel with each orbit?

Verdich [7]

Answer:

25748 km

Step-by-step explanation:

The distance at which astronauts travel can be obtained by calculating the Circumference of the circle.

Circumference of a circle = 2πr ; π = 3.14

Radius = 4100 km

Circumference of a circle = 2 * 3.14 * 4100

Circumference of the circle = 25748 km

Hence, astronauts travel a distance of 25748 km

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3 years ago

Help solving this include drawing of stars and written explanation

Elenna [48]

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4 years ago

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Setler79 [48]

Answer:

its a. rhejhdhrhrjdhr

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3 years ago