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zalisa [80]
4 years ago
5

Mandy collected 4 times as many shells as Cameron. Together they collected 40 shells. How many shells did Mandy collect. Write a

n equation and solve
Mathematics
1 answer:
MatroZZZ [7]4 years ago
6 0
10, because 40 divided by 4 is ten
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What is lim x→3 x^2 - x - 6/ x - 3
Kisachek [45]
<h3>Answer: D) 5</h3>

=======================================================

Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, \frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2

Allowing us to say,

\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\

5 0
4 years ago
Evaluate the following function for (3, -1):<br> f(x, y) = 2x – 3y + xy^2
satela [25.4K]

Answer:

f(3, -1) = 12

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x, y) = 2x - 3y + xy²

(3, -1) is x =3 and y = -1

<u>Step 2: Evaluate</u>

  1. Substitute:                    f(3, -1) = 2(3) - 3(-1) + 3(-1)²
  2. Exponents:                   f(3, -1) = 2(3) - 3(-1) + 3(1)
  3. Multiply:                        f(3, -1) = 6 + 3 + 3
  4. Add:                              f(3, -1) = 9 + 3
  5. Add:                              f(3, -1) = 12
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3 years ago
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