Answer:
a) 30.726m/s and b) 5.5549s
Step-by-step explanation:
a.) What was Chris Huber’s speed in meters per second(m/s)?
Given the distance and time, the formula to obtain the speed is
.
Applying this to our problem we have that
.
So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.
b) What was Whittingham’s time through the 200 m?
In a) we stated that . This formula implies that
.
First, observer that 
.
Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, 
Then, applying 1) we have that
So, Sam Whittingham’s time through the 200 m was 5.5549s.
The answer is A; a=50t cause if you were to put 0, you would get 0 which is the first point, if you put in 1 you get 50, if you put in 2 you get 100 and so on.
Answer:
yes
Step-by-step explanation:
Answer:
Mrs. Etercsid
Step-by-step explanation:
One thing we can do is just multiply the averages by the percents in each class and compare from there.
To get from percentages to decimals, we can divide by 100.
For Mr. Tats:
Homework: 25 % -> 0.25
Participation: 10% -> 0.1
Test: 40% -> 0.4
Final: 0.25 -> 0.25
For Mrs. Etercsid:
Homework: 15% -> 0.15
Participation: 10% -> 0.1
Test: 60% -> 0.6
Final: 15% -> 0.15
We can then multiply the averages by the decimals for each teacher and add them up.
Mr. Tats:
0.25 * 81 + 0.1 * 57 + 0.4 * 93 + 0.25 * 87 = 84.9
Mrs. Etercsid:
0.15 * 81 + 0.1 * 57 + 0.6 * 93 + 0.15 * 87 = 86.7
You would get the higher grade with Mrs. Etercsid
Answer: A, D
Step-by-step explanation:
68 is the initial amount.
A is correct because 0.2(68) represents 20% of 68. Since you're looking for 80% of 68, you subtract 0.2(68) from 68.
D is correct because it directly takes 80% of 68, which is what the question is asking for.
