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erma4kov [3.2K]
3 years ago
15

Find the product. (6x^2-6x-5) (7x^2+6x-5)

Mathematics
1 answer:
Kryger [21]3 years ago
4 0

The answer is for (6x^2-6x-5)(7x^2+6x-5) is B

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igomit [66]
It would be a negative number due to the fact that there are three negative numbers. A negative times a negative makes a positive, so because there are three it means the negative won't cancel out.
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I have picture of it
LiRa [457]

Answer:

basically multiply the prices by how much they filled up. That should give the answer.

Step-by-step explanation:

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2 years ago
For 1 and 2, use integer values of x from -3 to 3 to graph the equation
garri49 [273]
This would be an upside down parabola with a vertex at (0, 3).

To complete the chart, just plug x into the equation and evaluate.

Here is the completed table:

x      y
-3    -15
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3 0
3 years ago
1) Given: mLHE=84°<br><br>Find: m∠EYL. <br><br>2)Given: m∠EYL=72°<br>Find: m arc EHL, m arc LVE
SCORPION-xisa [38]

Answer:

Part 1) The measure of angle EYL is 96\°

Part 2) The measure of arc EHL is 108\° and the measure of arc LVE is 252\°

Step-by-step explanation:

we know that

The measurement of the outer angle is the semi-difference of the arcs which comprises

Part 1)

Let

x------> the measure of arc LHE

y----> the measure of arc LVE

we know that

x+y=360\°

x=84\°

Find the value of y

y=360\°-84\°=276\°

<em>Find the measure of angle EYL</em>

m

substitute the values

m

Part 2)

Let

x------> the measure of arc EHL

y----> the measure of arc LVE

we know that

x+y=360\°

x=360\°-y -----> equation A

m

m

substitute

72\°=\frac{1}{2} (y-x)

144\°=(y-x)

x=y-144\° --------> equation B

equate equation A and equation B and solve for y

360\°-y=y-144\°

2y=360\°+144\°

2y=504\°

y=252\°

Find the value of x

x=252\°-144\°=108\°

therefore

The measure of arc EHL is 108\°

The measure of arc LVE is 252\°

3 0
3 years ago
sons in the NHL,nts than anyone whoccomplished thiser games thanHer. Here are theRg each season:74, 45, 81, 48, 80,Working for a
vesna_86 [32]

Step 1:

In descriptive statistics, a box plot or boxplot (also known as box and whisker plot) is a type of chart often used in explanatory data analysis. Box plots visually show the distribution of numerical data and skewness through displaying the data quartiles (or percentiles) and averages.

Step 2:

To sketch a boxplot, you will need to determine the following:

Minimum

Lower quartile

Median

Upper quartile

Maximum

Step 3:

USA

First arrange the data from the least to the greatest.

14 , 26, 33, 34, 35, 38, 40, 41, 44, 46, 46, 49, 53, 66, 70.

Minimum = 14

\begin{gathered} \text{Lower quartile position = }\frac{1}{4}(n+1)^{th} \\ \text{= }\frac{15+1}{4}\text{ = }\frac{16}{4}=4^{th} \\ Q_1\text{ = lower quartile = 34} \end{gathered}

Median = 41

\begin{gathered} \text{Upper quartile position = }\frac{3}{4}(n+1)^{th} \\ =\text{ }\frac{3\text{ }\times(15+1)}{4} \\ =12^{th} \\ Q_3\text{ = upper quartile  = 49} \end{gathered}

Maximum = 70

Interquartile range IQR = 49 - 34 = 15

Canada

22, 28, 31, 31, 35, 35, 36, 39, 40, 40, 42, 49, 53, 63, 68

Minimum = 22

\begin{gathered} Q1\text{  Position = }\frac{(n+1)^{th}\text{ }}{4}\text{ = }\frac{16}{4}th=4^{th} \\ Q_1\text{ = 31} \end{gathered}

Median = 39

\begin{gathered} UpperquartileQ_{_3\text{ }}\text{ = 49} \\  \end{gathered}

Maximum = 68

Interquartile range = 49 - 31 = 18

8 0
1 year ago
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