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Pavlova-9 [17]
3 years ago
13

What is the value of a? -2(a - 8) + 6a = 36

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
5 0
     -2(a - 8) + 6a = 36
-2(a) + 2(8) + 6a = 36
     -2a + 16 + 6a = 36
     -2a + 6a + 16 = 36
              4a + 16 = 36
                    - 16  - 16
                       4a = 20
                        4      4
                          a = 5
Romashka-Z-Leto [24]3 years ago
5 0
Distribute -2

-2a + 16 + 6a = 36

Add like terms.

4a + 16 = 36

Factor out 4

4(a+4) = 36

Divide both sides by 4

a + 4 = 9

Subtract 4 on both sides

a = 5
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10/17 = d/51 solve for D
BabaBlast [244]
The answer is 30. You just multiply 51 by (10/17)
4 0
3 years ago
I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
Write an equation for each condition listed. The horizontal line that passes through (-7,4), The vertical line that passes throu
pashok25 [27]
Y=4 is the first one
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3 years ago
A psychologist is interested in knowing whether adults who were bullied as children differ from the general population in terms
MissTica

Answer:

t = \frac{39.5-30.6}{\frac{6.6}{\sqrt{25}}}= 6.74

The degrees of freedom are given by:

df =n-1= 25-1=24

Now we can calculate the p value with the following probability:

p_v = 2*P(t_{24}>6.74)= 5.69x10^{-7}

And for this case since the p value is lower compared to the significance level \alpha=0.05 we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05

Step-by-step explanation:

For this case we have the following info given:

\bar X = 39.5 represent the sample mean

s =6.6 represent the sample deviation

\mu = 30.6 represent the reference value to test.

n = 25 represent the sample size selected

The statistic for this case is given by:

t =\frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}

And replacing we got:

t = \frac{39.5-30.6}{\frac{6.6}{\sqrt{25}}}= 6.74

The degrees of freedom are given by:

df =n-1= 25-1=24

Now we can calculate the p value with the following probability:

p_v = 2*P(t_{24}>6.74)= 5.69x10^{-7}

And for this case since the p value is lower compared to the significance level \alpha=0.05 we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05

3 0
4 years ago
Plz I need your help
kirza4 [7]
The mode is 87 degrees.
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