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erastovalidia [21]
4 years ago
10

What is sin B=0.4848

Mathematics
1 answer:
Oksana_A [137]4 years ago
7 0
0.0084 is the answer.
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Simplify: 6 + √27 / 3
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Answer:

6 + √27 / 3

6+ (3√3/3)

6+√3

Step-by-step explanation:

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What are the solutions of the equation Z ^ 2 - 6z - 27 equals 0
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(z+3 )(z-9) = 0
 z+ 3 = 0 
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using the completing-the-square method find the vertex of the function f(x) = -2x^2 + 12x + 5 and indicate whether it is a minim
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The vertex is x = 3 and the maximum is at (3, 23)
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3 years ago
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are re
Anna35 [415]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

P(brown) = 12% = 0.12

P(Yellow) = 15% = 0.15

P(Red) = 12% = 0.12

P(blue) = 23% = 0.23

P(orange) = 23% = 0.23

P(green) = 15% = 0.15

A.) Compute the probability that a randomly selected peanut M&M is not yellow.

P(not yellow) = P(Yellow)' = 1 - P(Yellow) = 1 - 0.15 = 0.85

B.) Compute the probability that a randomly selected peanut M&M is brown or red.

P(Brown) or P(Red) :

0.12 + 0.12 = 0.24

C.) Compute the probability that three randomly selected peanut M&M’s are all brown.

P(brown) * P(brown) * P(brown)

0.12 * 0.12 * 0.12 =0.001728

D.) If you randomly select three peanut M&M’s, compute that probability that none of them are blue.

P(3 blue)' = 1 - P(3 blue)

P(3 blue) = 0.23 * 0.23 * 0.23 = 0.012167

1 - P(3 blue) = 1 - 0.012167 = 0.987833

If you randomly select three peanut M&M’s, compute that probability that at least one of them is blue.

P(1 blue) + p(2 blue) + p(3 blue)

(0.23) + (0.23*0.23) + (0.23*0.23*0.23)

0.23 + 0.0529 + 0.012167

= 0.295067

5 0
3 years ago
The line segment, AB has a point C as its midpoint. If A is at (1, 1) and C is at (4,3), what are the coordinates of the endpoin
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The correct answer is C 4,3
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4 years ago
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