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Sphinxa [80]
2 years ago
14

These box plots show daily low temperatures for a sample of days in two

Mathematics
1 answer:
lara [203]2 years ago
7 0

Answer:

d

Step-by-step explanation:

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Geometry Sem2 Quiz 1.2.1 - Isosceles Triangles<br> 2. Find the value of x.<br> x + 3<br> 12
nirvana33 [79]

Answer:

x = 9

Step-by-step explanation:

The angles in red are equivalent and the triangle is isosceles.

This means the sides with lengths 12 and x + 3 are equivalent.

x + 3 = 12

x + 3 - 3 = 12 - 3

x = 9

:)

5 0
3 years ago
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9(m-3)+3m=7m+43 help me please
nikdorinn [45]

Answer:

multiply 9 from m and -3

9m - 27 + 3m = 7m + 43

12m - 27 = 7m + 43

12m - 7m = 43+ 27

5m = 70 cut 70 by 5 in 14 times [ 14 x 5= 70 ]

m = 14 answer ❤️❤️ it is 100% correct now!

6 0
2 years ago
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The number y of cups of flour used to make x loaves of bread is represented by the equation y=2x. Graph the equation.
miv72 [106K]

Answer:

Step-by-step explanation:

Here you go! If you have more like these I recommend using Desmos Graphing calculator :)

3 0
2 years ago
Is there a cheating app to use to graph tangents
Rasek [7]

Answer:

You can user the application name Geogebra

Step-by-step explanation:

You can draw the graph of tangents and trigonometry

8 0
3 years ago
What is the quadratic regression equation for the data set? ​ ​ ​ <br><br> PLEASEE HELP ME
Soloha48 [4]
You're trying to find constants a_0,a_1,a_2 such that \hat y=a_0+a_1\hat x+a_2{\hat x}^2. Equivalently, you're looking for the least-square solution to the following matrix equation.


\underbrace{\begin{bmatrix}1&6&6^2\\1&3&3^2\\\vdots&\vdots&\vdots\\1&9&9^2\end{bmatrix}}_{\mathbf A}\underbrace{\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}}_{\mathbf x}=\underbrace{\begin{bmatrix}100\\110\\\vdots\\70\end{bmatrix}}_{\mathbf b}

To solve \mathbf{Ax}=\mathbf b, multiply both sides by the transpose of \mathbf A, which introduces an invertible square matrix on the LHS.

\mathbf{Ax}=\mathbf b\implies\mathbf A^\top\mathbf{Ax}=\mathbf A^\top\mathbf b\implies\mathbf x=(\mathbf A^\top\mathbf A)^{-1}\mathbf A^\top\mathbf b

Computing this, you'd find that

\mathbf x=\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}\approx\begin{bmatrix}121.119\\-3.786\\-0.175\end{bmatrix}

which means the first choice is correct.
8 0
3 years ago
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