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Lelechka [254]
3 years ago
9

Use the graph to write an equation y = acos[b(x – h)] + k to model the situation.

Mathematics
2 answers:
N76 [4]3 years ago
5 0

Answer:

vertical shift (k) is 50

Horizontal shift (h) is -1

Step-by-step explanation:

inna [77]3 years ago
3 0

Answer:The amplitude:30

so a:-30

the period is:12

so b: pi/6

Step-by-step explanation:

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Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.
Otrada [13]

I guess the "5" is supposed to represent the integral sign?

I=\displaystyle\int_1^4\ln t\,\mathrm dt

With n=10 subintervals, we split up the domain of integration as

[1, 13/10], [13/10, 8/5], [8/5, 19/10], ... , [37/10, 4]

For each rule, it will help to have a sequence that determines the end points of each subinterval. This is easily, since they form arithmetic sequences. Left endpoints are generated according to

\ell_i=1+\dfrac{3(i-1)}{10}

and right endpoints are given by

r_i=1+\dfrac{3i}{10}

where 1\le i\le10.

a. For the trapezoidal rule, we approximate the area under the curve over each subinterval with the area of a trapezoid with "height" equal to the length of each subinterval, \dfrac{4-1}{10}=\dfrac3{10}, and "bases" equal to the values of \ln t at both endpoints of each subinterval. The area of the trapezoid over the i-th subinterval is

\dfrac{\ln\ell_i+\ln r_i}2\dfrac3{10}=\dfrac3{20}\ln(ell_ir_i)

Then the integral is approximately

I\approx\displaystyle\sum_{i=1}^{10}\frac3{20}\ln(\ell_ir_i)\approx\boxed{2.540}

b. For the midpoint rule, we take the rectangle over each subinterval with base length equal to the length of each subinterval and height equal to the value of \ln t at the average of the subinterval's endpoints, \dfrac{\ell_i+r_i}2. The area of the rectangle over the i-th subinterval is then

\ln\left(\dfrac{\ell_i+r_i}2\right)\dfrac3{10}

so the integral is approximately

I\approx\displaystyle\sum_{i=1}^{10}\frac3{10}\ln\left(\dfrac{\ell_i+r_i}2\right)\approx\boxed{2.548}

c. For Simpson's rule, we find a quadratic interpolation of \ln t over each subinterval given by

P(t_i)=\ln\ell_i\dfrac{(t-m_i)(t-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+\ln m_i\dfrac{(t-\ell_i)(t-r_i)}{(m_i-\ell_i)(m_i-r_i)}+\ln r_i\dfrac{(t-\ell_i)(t-m_i)}{(r_i-\ell_i)(r_i-m_i)}

where m_i is the midpoint of the i-th subinterval,

m_i=\dfrac{\ell_i+r_i}2

Then the integral I is equal to the sum of the integrals of each interpolation over the corresponding i-th subinterval.

I\approx\displaystyle\sum_{i=1}^{10}\int_{\ell_i}^{r_i}P(t_i)\,\mathrm dt

It's easy to show that

\displaystyle\int_{\ell_i}^{r_i}P(t_i)\,\mathrm dt=\frac{r_i-\ell_i}6(\ln\ell_i+4\ln m_i+\ln r_i)

so that the value of the overall integral is approximately

I\approx\displaystyle\sum_{i=1}^{10}\frac{r_i-\ell_i}6(\ln\ell_i+4\ln m_i+\ln r_i)\approx\boxed{2.545}

4 0
3 years ago
I need the answer! Please help me!
AleksAgata [21]
He needs to work 22 hours :)
6 0
3 years ago
Read 2 more answers
Some numbers are 1/4 as large as another number. the difference of a number is 12.
Eddi Din [679]

Answer:

Step-by-step explanation:

x = ¼y

y - x = 12

y - ¼y = 12

¾y = 12

y = 16

x = ¼y = 4

3 0
3 years ago
Each cube in this rectangular prism is 1 cm3.What is the volume of the rectangular prism?
Lelechka [254]

Answer:

Volume of rectangular prism = 20\ cm^3

Step-by-step explanation:

Given rectangular prism is made up of small cubes of volume 1 cubic centimeter.

To find volume of rectangular prism.

Solution:

Volume of rectangular prism is = length\times width \times height

We know that all sides of a cube are equal in measure.

So, we will count the number of cubes on each side to get the exact measure.

Length side = 4 cubes = 5 cm

Width side = 2 cubes = 2 cm

Height side = 2 cubes = 2 cm

Thus volume of rectangular prism =  5\ cm\times 2\ cm \times 2\ cm

Volume of rectangular prism = 20\ cm^3

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3 years ago
Solve: (3-x)(4x+3)<(2x-1)(3-x)
sergiy2304 [10]

Please refer to the above attachment

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