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3 years ago

Help?... 1/3(-3) + 13

Mathematics

2 answers:

ra1l [238]3 years ago

7 0

Answer: 12

Step-by-step explanation:

Veronika [31]3 years ago

3 0

Answer:

Step-by-step explanation:

1/3(-3)=-1

-1+13=12

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F(x) = -2(x + 2)2 + 4

USPshnik [31]

Answer:

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Step-by-step explanation: H-JJ-

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2 years ago

Five members of the soccer team and five members of the track team ran the 100-meter dash. Their times are listed in the table b

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3 years ago

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Yuliya22 [10]

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2 years ago

Number when multiplied by 0.5?<br> Which number produces a rational

Vladimir79 [104]

I don’t really know what your asking but anything multiplied by 0.5 or .5 is going to be half of that number
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I don’t know if this is what you were asking, but I hope this helps

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2 years ago

A random sample of 864 births in a state included 426 boys. Construct a 95% confidence interval estimate of the proportion of bo

oksian1 [2.3K]

Using the z-distribution, it is found that the 95% confidence interval is (0.46, 0.526), and it does not provide strong evidence against that belief.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

We have that a random sample of 864 births in a state included 426 boys, hence the parameters are given by:

$n = 864, \pi = \frac{426}{864} = 0.493$

Then, the bounds of the interval are given by:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.493 - 1.96\sqrt{\frac{0.493(0.507)}{864}} = 0.46$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.493 + 1.96\sqrt{\frac{0.493(0.507)}{864}} = 0.526$

The 95% confidence interval estimate of the proportion of boys in all births is (0.46, 0.526). Since the interval contains 0.506, it does not provide strong evidence against that belief.

More can be learned about the z-distribution at brainly.com/question/25890103

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2 years ago