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Nina [5.8K]
3 years ago
6

A sonar operator on a battleship looks at a display that contains a spatial layout of the distribution of echoes from the surrou

nding ocean. A submarine appears as a more intense cluster of echoes. We can think of this as a signal detection problem. The sonar operator looks at the display an ________
Computers and Technology
1 answer:
ankoles [38]3 years ago
8 0

Answer:

The sonar operator looks at the display a forms an internal representation of the strength of the evidence that a submarine is present. If this exceeds an internal, subjective threshold,the sonar operator tells the captain that a submarine is present.

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Note: the println() function prints out a line of text with the value that you pass to it - so if you say println("Hi"), it will
Paul [167]

The answer to this is 9choice B) or hi  hi

hope this is helpful

8 0
3 years ago
Create an integer variable named ‘listSize’ and initialize the value to 1000.
Natalija [7]

Answer:

The code is given in C++. The variable name is arraySize. It should be replaced with listSize

Explanation:

// header file

#include<iostream>

#include<fstream>

#include<cstdlib>

#include<chrono>

using namespace std;

using namespace std::chrono;

// bubble sort algorithm

void bubbleSort(int *a, int size) {

for (int i = 0; i<size - 1; i++) {

for (int j = 0; j<size - i - 1; j++) {

if (a[j]>a[j + 1]) {

//swap

int temp = a[j];

a[j] = a[j + 1];

a[j + 1] = temp;

}

}

}

}

// selection sort

void selectionSort(int *a, int size) {

for (int i = 0; i<size - 1; i++) {

int m_i = i;

for (int j = i + 1; j<size; j++) {

if (a[j]<a[m_i]) {

m_i = j;

}

}

//swap

int temp = a[i];

a[i] = a[m_i];

a[m_i] = a[i];

}

}

// insertion sort

void insertionSort(int *a, int size) {

for (int i = 1; i<size; ++i) {

int key = a[i];

int j=i-1;

for (; (j >= 0 && key < a[j]); j--) {

a[j + 1] = a[j];

}

a[j + 1] = key;

}

}

// make partition on array

int getPartition(int *a, int l, int h) {

int pvt = a[h];

int i = (l - 1);

for (int j = l; j <= h - 1; j++) {

if (a[j]<pvt) {

i++;

//swap

int tmp = a[i];

a[i] = a[j];

a[j] = tmp;

}

}

//swap

int tmp = a[i + 1];

a[i + 1] = a[h];

a[h] = tmp;

return(i + 1);

}

// quick sort

void quickSort(int *a, int l, int h) {

if (l<h) {

int p = getPartition(a, l, h);

quickSort(a, l, p - 1);

quickSort(a, p + 1, h);

}

}

// merge array

void merge(int *a, int l, int m, int r) {

int n1 = m - l + 1;

int n2 = r - m;

int *L = new int[n1];

int *R = new int[n2];

for (int i = 0; i<n1; i++) {

L[i] = a[i + l];

}

for (int j = 0; j<n2; j++) {

R[j] = a[m + j + 1];

}

int i = 0, j = 0, k = 1;

while (i<n1 && j<n2) {

if (L[i] <= R[j]) {

a[k] = L[i];

i++;

}

else {

a[k] = R[j];

j++;

}

k++;

}

while (i<n1) {

a[k] = L[i];

i++;

k++;

}

while (j<n2) {

a[k] = R[j];

j++;

k++;

}

}

// merge sort

void mergeSort(int *a, int l, int r) {

if (l<r) {

int m = l + (r - l) / 2;

mergeSort(a, l, m);

mergeSort(a, m + 1, r);

merge(a, l, m, r);

}

}

int* randomData(int size) {

int *ar = new int[size];

for (int i = 0; i<size; i++) {

ar[i] = rand();

}

return(ar);

}

void copyAry(int *a, int *b, int size) {

for (int i = 0; i < size; i++) {

a[i] = b[i];

}

}

int main() {

int arraySize = 1000;

int *arrLst = new int[arraySize];

int *arLst = new int[arraySize];

arrLst = randomData(arraySize);

//copy array

// because after sorting arry will be sorted

copyAry(arLst, arrLst, arraySize);

auto start1 = high_resolution_clock::now();

bubbleSort(arLst, arraySize);

auto end1 = high_resolution_clock::now();

auto duration1 = duration_cast<microseconds>(end1 - start1);

cout << duration1.count()<<endl;

// copy array for new sort

copyAry(arLst, arrLst, arraySize);

auto start2 = high_resolution_clock::now();

selectionSort(arLst, arraySize);

auto end2 = high_resolution_clock::now();

auto duration2 = duration_cast<microseconds>(end2 - start2);

cout << duration2.count() << endl;

// copy array for new sort

copyAry(arLst, arrLst, arraySize);

auto start3 = high_resolution_clock::now();

insertionSort(arLst, arraySize);

auto end3 = high_resolution_clock::now();

auto duration3 = duration_cast<microseconds>(end3 - start3);

cout << duration3.count() << endl;

// copy array for new sort

copyAry(arLst, arrLst, arraySize);

auto start4 = high_resolution_clock::now();

mergeSort(arLst, 0,arraySize-1);

auto end4 = high_resolution_clock::now();

auto duration4 = duration_cast<microseconds>(end4 - start4);

cout << duration4.count() << endl;

// copy array for new sort

copyAry(arLst, arrLst, arraySize);

auto start5 = high_resolution_clock::now();

quickSort(arLst, 0,arraySize-1);

auto end5 = high_resolution_clock::now();

auto duration5 = duration_cast<microseconds>(end5 - start5);

cout << duration5.count() << endl;

ofstream out("GroupAssignment2Results.csv");

out << "Array Size,Bubble Sort Time,Selection Sort Time,Insertion Sort Time,Quick Sort Time,Merge Sort Time\n";

out << arraySize << "," << duration1.count() << "," << duration2.count() << "," << duration3.count() << "," << duration5.count() << "," << duration4.count();

cout << "\nOutput in File.";

out.close();

cin.get();

return(0);

}

3 0
3 years ago
What is GIGO ?<br>plz answer me​
DanielleElmas [232]

Answer:

Garbage in, garbage out

Explanation:

In computer science, garbage in, garbage out is the concept that flawed, or nonsense input data produces nonsense output or garbage

4 0
2 years ago
Wich type of operating system is usually used in personal computers
Anvisha [2.4K]
The three most common operating systems for personal computers are Microsoft Windows, Apple Mac OS X, and Linux.
4 0
3 years ago
Read 2 more answers
(1) Prompt the user for an automobile service. Output the user's input. (1 pt) Ex: Enter desired auto service: Oil change You en
Pavlova-9 [17]

Answer:

In Python:

#1

service = input("Enter desired auto service: ")

print("You entered: "+service)

#2

if service.lower() == "oil change":

   print("Cost of oil change: $35")

elif service.lower() == "car wash":

   print("Cost of car wash: $7")

elif service.lower() == "tire rotation":

   print("Cost of tire rotation: $19")

else:

   print("Invalid Service")

Explanation:

First, we prompt the user for the auto service

service = input("Enter desired auto service: ")

Next, we print the service entered

print("You entered: "+service)

Next, we check if the service entered is available (irrespective of the sentence case used for input). If yes, the cost of the service is printed.

This is achieved using the following if conditions

For Oil Change

<em>if service.lower() == "oil change":</em>

<em>    print("Cost of oil change: $35")</em>

For Car wash

<em>elif service.lower() == "car wash":</em>

<em>    print("Cost of car wash: $7")</em>

For Tire rotation

<em>elif service.lower() == "tire rotation":</em>

<em>    print("Cost of tire rotation: $19")</em>

Any service different from the above three, is invalid

<em>else:</em>

<em>    print("Invalid Service")</em>

<em></em>

6 0
3 years ago
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