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3 years ago

11

The function h (x) = StartFraction 1 Over x squared + 1 EndFraction is the result of the composition f(g(x)). If g(x) = x2 + 1,

what is f(x)

1 answer:

dem82 [27]3 years ago

7 0

Answer: 1/x

Step-by-step explanation:

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Please help! Picture included!!!

V125BC [204]

The answer is c)32 hope this helps

5 0

3 years ago

Read 2 more answers

Consider the function f(x)=x3+6x2−20x+450.

Damm [24]

Answer:

Therefore reminder = 2802

Step-by-step explanation:

f(x)=x³+6x²-20x+450

x-12)x³+6x²-20x+450(x²+18x+196

x³-12x²

____________________

+18x²-20x+450

18x²-216x

_______________

196x +450

196x-2352

_____________

2802

Therefore reminder = 2802

6 0

2 years ago

In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro

VladimirAG [237]

Answer:

Margin of error for a 95% of confidence intervals is 0.261

Step-by-step explanation:

<u>Step1:-</u>

Sample n = 81 business students over a one-week period.

Given the population standard deviation is 1.2 hours

Confidence level of significance = 0.95

Zₐ = 1.96

Margin of error (M.E) = $\frac{Z_{\alpha }S.D }{\sqrt{n} }$

Given n=81 , σ =1.2 and Zₐ = 1.96

<u>Step2:-</u>

<u /> $Margin of error (M.E) = \frac{Z_{\alpha }S.D }{\sqrt{n} }$ <u />

<u /> $Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }$ <u />

On calculating , we get

Margin of error = 0.261

<u>Conclusion:-</u>

Margin of error for a 95% of confidence intervals is 0.261

<u />

4 0

3 years ago

How do I solve: 2 sin (2x) - 2 sin x + 2√3 cos x - √3 = 0

ziro4ka [17]

Answer:

$\displaystyle x = \frac{\pi}{3} +k\, \pi$ or $\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ , where $k$ is an integer.

There are three such angles between $0$ and $2\pi$ : $\displaystyle \frac{\pi}{3}$ , $\displaystyle \frac{2\, \pi}{3}$ , and $\displaystyle \frac{4\,\pi}{3}$ .

Step-by-step explanation:

By the double angle identity of sines:

$\sin(2\, x) = 2\, \sin x \cdot \cos x$ .

Rewrite the original equation with this identity:

$2\, (2\, \sin x \cdot \cos x) - 2\, \sin x + 2\sqrt{3}\, \cos x - \sqrt{3} = 0$ .

Note, that $2\, (2\, \sin x \cdot \cos x)$ and $(-2\, \sin x)$ share the common factor $(2\, \sin x)$ . On the other hand, $2\sqrt{3}\, \cos x$ and $(-\sqrt{3})$ share the common factor $\sqrt[3}$ . Combine these terms pairwise using the two common factors:

$(2\, \sin x) \cdot (2\, \cos x - 1) + \left(\sqrt{3}\right)\, (2\, \cos x - 1) = 0$ .

Note the new common factor $(2\, \cos x - 1)$ . Therefore:

$\left(2\, \sin x + \sqrt{3}\right) \cdot (2\, \cos x - 1) = 0$ .

This equation holds as long as either $\left(2\, \sin x + \sqrt{3}\right)$ or $(2\, \cos x - 1)$ is zero. Let $k$ be an integer. Accordingly:

$\displaystyle \sin x = -\frac{\sqrt{3}}{2}$ , which corresponds to $\displaystyle x = -\frac{\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = -\frac{2\, \pi}{3} + 2\, k\, \pi$ .
$\displaystyle \cos x = \frac{1}{2}$ , which corresponds to $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ and $\displaystyle x = -\frac{\pi}{3} + 2\, k \, \pi$ .

Any $x$ that fits into at least one of these patterns will satisfy the equation. These pattern can be further combined:

$\displaystyle x = \frac{\pi}{3} + k \, \pi$ (from $\displaystyle x = -\frac{2\,\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ , combined,) as well as
$\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ .

7 0

3 years ago

3n+75=50+2n please help righting more

alexandr1967 [171]

Answer: n = -25

Step-by-step explanation:

you would need to get N by itself so you would subtract 2n from both sides and that would bring you to n+75=50 and then you would need to subtract 75 from both sides and that leads you to n=-25

5 0

2 years ago