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Elis [28]
3 years ago
13

For (x)=3x+1 and g(x)=x^2 -6, find (f+g)(x)

Mathematics
1 answer:
julsineya [31]3 years ago
4 0

Answer:

<h2>(f + g)(x) = x² + 3x - 5</h2>

Step-by-step explanation:

(f+g)(x)=f(x)+g(x)\\\\f(x)=3x+1;\ g(x)=x^2-6\\\\(f+g)(x)=(3x+1)+(x^2-6)=x^2+3x+1-6=x^2+3x-5

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4 0
3 years ago
WILL MARK BRAINLIEST
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Answer:

512

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3 years ago
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3 years ago
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Katena32 [7]

Answer:

a = -6

b = 1

Step-by-step explanation:

The gradient of the tangent to the curve y = ax + bx^3, will be:

dy/dx = a + 3bx²

at (2, -4)

dy/dx = a+3b(2)²

dy/dx = a+12b

Since the gradient at the point is 6, then;

a+12b = 6 ....1

Substitute x = 2 and  y = -4 into the original expression

-4 = 2a + 8b

a + 4b = -2 ...2

a+12b = 6 ....1

Subtract

4b - 12b = -2-6

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b = -8/-8

b = 1

Substitute b = 1 into equation 1

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a+12(1) = 6

a = 6 - 12

a = -6

Hence a = -6, b = 1

5 0
3 years ago
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