I think the order should be 2-1-3-4, but the description of step 1 is confusing. In selection sort, you iterate from the point of the marker down through the entire list and find the smallest value, and swap that with the value at the marker. Then you advance the marker and repeat the process on the remainder of the list.
Answer:
a system that is a computer
Answer:
#include<iostream>
using namespace std;
int lcm(int m, int n) {
int a;
a = (m > n) ? m: n;
while (true) {
if (a % m == 0 && a % n == 0)
return a;
++a;
}
}
int gcd(int m, int n) {
int r = 0, a, b;
a = (m > n) ? m : n;
b = (m < n) ? m : n;
r = b;
while (a % b != 0) {
r = a % b;
a = b;
b = r;
}
return r;
}
int main(int argc, char **argv) {
cout << "Enter the two numbers: ";
int m, n;
cin >> m >> n;
cout << "The LCM of two numbers is: " << lcm(m, n) << endl;
cout << "The GCD of two numbers is: " << gcd(m, n) << endl;
return 0;
}
Explanation:
Answer:
The encoding algorithm looks for pairs of characters that appear in the string more than once and replaces each instance of that pair with a corresponding character that does not appear in the string. ... Byte pair encoding is an example of a lossy transformation because it discards some of the data in the original string.
Explanation:
hope it helps!!
