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Gre4nikov [31]
3 years ago
14

Hey! I could really use some help! I need this done by 2PM Mountain Time please! Also, I need it typed In any pictures as an asn

wer I can't see. ;(

Mathematics
2 answers:
grigory [225]3 years ago
7 0
Just find the y intercept for both lines and calculate the change in y with respect to the x axis, aka slope. You can write an equation from any line by doing what I just said. The y-intercept is the y value where the function intercepts the y-axis.

Red Line:
Y-intercept = 2
Slope = 1/1

Blue Line:
Y-intercept = 4
Slope = -1/2

And you should know the equation, atleast I hope you do.
y = mx + b
m being the slope
b being the y-intercept

You now got:
y = x + 2
and
y = -(1/2)x + 4

Make them equal to each other since they are both equal to y. Solve for x and then solve for the actual y value. I don’t want to do everything for you, since you wouldn’t really learn anything
yKpoI14uk [10]3 years ago
4 0

Answer:

The red one would be x+2

It begins at 2 and it increases by 1 at a time

You might be interested in
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

5 0
3 years ago
NEED HELP PLEASE
ludmilkaskok [199]

Answer:

16 feet, 18 feet, and 25 feet.

Step-by-step explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
4 0
3 years ago
Two mathematical questions attached below.
BartSMP [9]

Answer:

See below

Step-by-step explanation:

9.( {m}^{3}  {n}^{5} )^{ \frac{1}{4} }   \\   =  m^{\frac{3}{4}}n^{\frac{5}{4}}\\  \\ 10. \sqrt[5]{ \sqrt[4]{x} }  \\  =  \sqrt[5]{ {x}^{ \frac{1}{4} } }  \\  =  {( {x}^{ \frac{1}{4} } )}^{ \frac{1}{5} }  \\   =  {x}^{ \frac{1}{4}  \times  \frac{1}{5} }  \\  =  {x}^{ \frac{1}{20} }  \\  \\ \sqrt[5]{ \sqrt[3]{ {a}^{2} } }  \\  =  \sqrt[5]{ {a}^{ \frac{2}{3} } }  \\  =  {( {a}^{ \frac{2}{3} } )}^{ \frac{1}{5} }  \\   =  {a}^{ \frac{2}{3}  \times  \frac{1}{5} }  \\  =  {a}^{ \frac{2}{15} }

4 0
2 years ago
What is the measure of ∠S ?
jeka94

Alright, lets get started.

We could use sine law to find the remaining angle.

\frac{sinA}{a} =  \frac{sinB}{b}

\frac{sinS}{63.6}  = \frac{sin64}{69.8}

Plugging the value of sin 64

\frac{sinS}{63.6} =  \frac{0.8987}{69.8}

\frac{sinS}{63.6} = 0.01287

Cross multiplying

sin S = 0.8189

Taking inverse on both side

S = sin^{-1}(0.8189)

S = 55° : Answer

Hope it will help :)



4 0
3 years ago
Read 2 more answers
Neeeeeeeddd tooo much helplpp
MariettaO [177]
Hello there. I believe it’s c
8 0
3 years ago
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