Answer:
A,c,e
Step-by-step explanation:
Let a and d be the first term and common difference, respectively. Then
the 8th term is a+7d
the 20th term is a+19d
The sum of the first 8 terms is
(a)+(a+d)+(a+2d)+...+(a+7d) = 8a+28d
The sum of the first 20 terms is
(a)+(a+d)+(a+2d)+...+(a+19d) = 20a+190d
So
8a + 28d = 160
20a+ 190d = 880
40a + 140d = 800
40a + 380d = 1760
240d = 960
d = 4
8a + 112 = 160
8a=48
a =
6
The first term is 6 and the common difference is 4.
The 43rd term is a+42d = 6+42(4) = 6+168 = 174
The sum of the first 12 terms is
(a)+(a+d)+(a+2d)+...+(a+11d) = 12a+66d = 12(6)+66(4) = 72+264 = 336
Answer: -1.1
The answer is: Negative 1 point 1 : -1.1
Answer:
9: D 10: A
Step-by-step explanation:
