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Akimi4 [234]
3 years ago
7

10 − 7j + 7 = -10 − 4j What is j

Mathematics
2 answers:
Elena L [17]3 years ago
7 0
Add the numbers 7 + 10
17 - 7j = -10 - 4j
subtract 17 from both sides
-7j = -27 - 4j
add 4j to both sides
-3j = -27
divide both sides by -3
j = 9
lorasvet [3.4K]3 years ago
4 0
First start with subtracting ten on each side and subtracting 7 on each side, then add 4j to the -7j to get 3j/3 = -27/3 which equals j=9 ; answer is j=9

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2. At 1 pm, you leave Ellensburg at a constant speed of 75 miles per hour. At 2:30 pm, your
MA_775_DIABLO [31]

Here, we are required to determine how many hours your friend will drive in order to catch you.

(a)<em> Your friend will have to drive 7 and a half hours inorder to catch </em><em>you.</em>

<em>(</em><em>b)</em><em> </em><em>You </em><em>both </em><em>will </em><em>be </em><em>6</em><em>7</em><em>5</em><em> </em><em>miles</em> <em>away </em><em>from </em><em>Ellensburg</em><em> </em><em>at </em><em>that </em><em>time.</em>

If you leave at 1 pm; At 2:30pm;

  • That is; 1 and a half hours after leaving; you must have covered a distance, d = 75 × 1.5
  • d = 112.5miles.

Therefore, your position; S after 2:30pm is given by;

S(a) = 75t + 112.5 miles from Ellensburg.

For your friend; travelling at 90miles/hr;

  • His position is given as; S(b) = 90 × t

(a) For your friend to catch you, you both must be in the same position;

  • i.e S(a) = S(b)

75t + 112.5 = 90t

90t -75t = 112.5

t = 112.5/15

t = 7.5hours

(b) To determine how far you both are from Ellensburg; we can either evaluate:

S(b) = 90t or S(a) = 75t + 112.5

Therefore, By evaluating S(b) = 90t.

S(b) = 90 × 7.5

S(b) = 675miles from Ellensburg.

Read more:

brainly.com/question/24234606

6 0
1 year ago
Read 2 more answers
A pair of equations is shown below:
Archy [21]

Slope Intercept Form - y = mx + b

First you need the slope or m which in the first equation is 6 and in the second is 5

Next the y-intercept or b which in the first equation is -4 and in the second is -3

Here is an image of both equation plotted on a graph where the first equation is purple and the second is green

Hope this helps, if you need anything else i will edit it in :)

edit: The to lines intercept at the point (1,2)

Sorry, i wasn't completely sure what you needed i haven't done this in a while. If you still need more, I'll try to help.

4 0
3 years ago
Read 2 more answers
Please answer this correctly without making mistakes
katrin2010 [14]

Answer:

16 km

Step-by-step explanation:

Given:

Distance from Washington to Stamford = distance from Washington to Salem + distance from Salem to Stamford = 10.3 km + 11.9 km = 22.2 km

Distance from Washington to Oakdele = 6.2 km

Required: the difference between the distance from Washington to Stamford and from Washington to Oakdele

Solution:

Distance from Washington to Stamford = 22.2 km

Distance from Washington to Oakdele = 6.2 km

The difference = 22.2 km - 6.2 km = 16 km

Therefore, from Washington, it is 16 km farther to Stamford than to Oakdele.

8 0
3 years ago
Ashley flies a drone 2,530 ft in 5 s. At this rate how many miles does the drone fly in a minute? 1 mi = 5280 ft
Klio2033 [76]

Answer:

I think the answer is 5.75 miles.

Step-by-step explanation:

If the drone flies 2,530 ft in 5 seconds, that means that in one minute it flies 30,360 ft. And 30,360 divided by 5,280 is 5.75.

3 0
3 years ago
Write 5.35 x 10 to the negative third power in standard form.
mote1985 [20]
0.00535. When there is a negative power move the decimal to the left
8 0
3 years ago
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