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3 years ago

Write the point-slope form of the line that passes through (5, 5) and is perpendicular to a line with a slope of 1/4.

1 answer:

6 0

A perpendicular line would have a slope that is the negative reciprocal of the slope you are given. Therefore the slope of the new line would be -4/1 or just -4.
You can now use point-slope formula and plug in your numbers to figure out the equation of that line.
Point-Slope form: y-y1=m(x-x1)
Therefore your equation would be: y-5=-4(x-5)

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Whats the midline equation ?

PSYCHO15rus [73]

Answer:

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Step-by-step explanation:

8 0

3 years ago

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The answer, and work shown.

hoa [83]

Slope= 1/2
Y intercept= (0,2)

Explanation:
Slope-intercept form is y=mx+b
-2x+4y=8
-8-2x=-4y
Divide by -4
2+1/2x=y

Y=1/2x+2

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3 years ago

considering the leading term of the polynomial function. what is the end behavior of the graph? describe the end behavior and pr

mario62 [17]

The leading term of polynomial function is the the term contain highest degree so here in the given question leading term is $-3x^5$

and leading coefficient is the coefficient of the term with greatest exponent -3

RULES for End behaviour

we have following four cases

CASE1: Even degree and positive leading coefficient

$x\rightarrow -\infty$ $f(x)\rightarrow \infty$

$x\rightarrow \infty$ $f(x)\rightarrow \infty$

CASE2: Even degree and negative leading coefficient

$x\rightarrow -\infty$ $f(x)\rightarrow -\infty$

$x\rightarrow \infty$ $f(x)\rightarrow -\infty$

CASE3: Odd degree and positive leading coefficient

$x\rightarrow -\infty$ $f(x)\rightarrow -\infty$

$x\rightarrow \infty$ $f(x)\rightarrow \infty$

CASE4: Odd degree and negative leading coefficient

$x\rightarrow -\infty$ $x\rightarrow \infty$

$x\rightarrow \infty$ $f(x)\rightarrow -\infty$

Here in the given case we have odd degree and negative leading coefficient

$x\rightarrow -\infty$ $x\rightarrow -\infty$

$x\rightarrow \infty$ $f(x)\rightarrow -\infty$

3 0

3 years ago

What is the y-inercept of the graph of f

Alexxx [7]

y-intercept is where the line on your graph crosses through the y-axis

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3 years ago

8x+3y=4 -7x+5y=-34 Elimination using multiplication

irga5000 [103]

Answer:

x= 2 and y = -4

Step-by-step explanation:

8x + 3y = 4 ---------------------------------(1)

-7x + 5y = -34 -----------------------------(2)

Multiply through equation (1) by 5 and multiply through equation(2) by 3

40x + 15y = 20 ----------------------------(3)

-21x + 15y =-102----------------------------(4)

Subtract equation (4) from equation (3)

61x = 122

Divide both-side of the equation by 61

61x/61 = 122/61

(At the left-hand side of the equation 61 will cancel-out 61 leaving us with just x, while at the left-hand side of the equation 122 will be divided by 61)

x = 122/61

x=2

Substitute x= 2 into equation (1)

8x + 3y = 4

8(2) + 3y = 4

16 + 3y = 4

Subtract 16 from both-side of the equation

16-16 + 3y = 4-16

3y = -12

Divide both-side of the equation by 3

3y/3 = -12/3

y = -4

x= 2 and y = -4

4 0

3 years ago

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