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Ivenika [448]
3 years ago
7

What is the solution to the inequality? 6x−5>−29

Mathematics
2 answers:
alisha [4.7K]3 years ago
5 0

Answer:

Solution of the inequality 6x-5> -29 is x > -4 or (-4, \infty)

Step-by-step explanation:

Given the inequality:

6x-5> -29

Add 5 to both sides we get;

6x-5+ 5> -29+5

Simplify:

6x> -24

Divide both sides by 6 we get;

x> -4

Therefore, the solution of the given inequality is, x > -4 or (-4, \infty)

Varvara68 [4.7K]3 years ago
3 0
Hi Brainiac

6x - 5 > -29
6x > -29 + 5
6x > -24
x > -24/6
x > -4

 
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4 years ago
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Answer:

1

Step-by-step explanation:

PEMDAS

6/ 2(1+2)

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6 0
3 years ago
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Which table describes the behavior of the graph of f(x) = 2x3 – 26x – 24?
In-s [12.5K]

Answer:

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

Step-by-step explanation:

f(x)=2x^{3}-26x-24

2x^{3}-26x-24=0

2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\

=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\

=> x-4=0\\=> x_{2}=4\\=> x+3=0\\=>x_{3}=-3\\

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis



7 0
4 years ago
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irinina [24]

Answer:

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Step-by-step explanation:

The distances have the ratio ...

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  Q = P +(2/3)R -(2/3)P = (2R +P)/3

  Qy = (2Ry +Py)/3 = (2·0 +7)/3 = 7/3

8 0
3 years ago
Whats the area of a square that is 9m and 9m?
siniylev [52]

Answer:

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Step-by-step explanation:

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If the side-length is 9, we can do:

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A = 81 m²

6 0
4 years ago
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