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posledela
4 years ago
6

Whats the area of a square that is 9m and 9m?

Mathematics
2 answers:
nirvana33 [79]4 years ago
7 0

Step-by-step explanation:

<u>Step 1:  Find the area</u>

An area of a square has a formula of → A= s^2

A = 9 * 9

A = 81

Answer:  Area=81m^2

siniylev [52]4 years ago
6 0

Answer:

81 m².

Step-by-step explanation:

To find the area of a square, you will simply need to do the side-length squared, or A= l^{2}.

If the side-length is 9, we can do:

A = 9²

A = 81 m²

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Which statement about 4x2 + 19x – 5 is true?
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Answer:

(x+5)

Step-by-step explanation:

=>4x^2+19x-5\\=>4x^2+20x-x-5\\=>4x(x+5)-1(x+5)\\=>(x+5)(4x-1)

Here, (x + 5) matches your answer choices

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A shop repairs both audio and video components. Let A denote the event that the next component brought in for repair is an audio
kow [346]

Answer: 0.6

Step-by-step explanation:

The probability formula to find p(B/A) is :

P(B/A) = p(A n B) / p(B)

Which means that A is contain in B and p(A n B) is p(A)

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Therefore

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5 0
4 years ago
State the slope and the y-intercept of this equation: y = -4x - 9
Lana71 [14]

Answer:

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The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

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4 years ago
Texas University Quarterback, Michael Daniels, is standing on his own 10-yard line. He throws a pass tword the opposite goal lin
dimulka [17.4K]

Answer: The function is y=-\frac{28}{625}(x-35)^2+30.

Explanation:

It is given that Michael Daniels, is standing on his own 10-yard line. He throws a pass toward the opposite goal line. The football is 2 yards above the ground when the quarterback lets it go.

It follows a parabolic path. Reaching its highest point, 30 yards above the ground. It is caught 50 yards downfield at a point 2 yards above the ground.

So, the initial point is (10,2) and the other point is (60,2).

The height function of a football represents a downward parabola. The maximum point of the function is called vertex. So the vertex is (h,30).

The two point (10,2) and (60,2) have same y-coordinate, therefore the function is maximum at the midpoint of both points.

midpoint=(\frac{10+60}{2}, \frac{2+2}{2})=(35,2)

So, the function is maximum at x=35. Hence the vertex is (35,30)

The standard form of the parabola is,

y=a(x-h)^2+k

Where (h,k) is vertex and a is scale factor.

Since vertex is (35,30).

y=a(x-35)^2+30

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2=a(10-35)^2+30

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a=-\frac{28}{625}

So the function of height is.

y=-\frac{28}{625}(x-35)^2+30

The graph of the function is shown below.

3 0
3 years ago
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