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lapo4ka [179]
4 years ago
11

Write an equivalent expression to 9y -1/2(4y+20)

Mathematics
2 answers:
suter [353]4 years ago
7 0
<span>9y -1/2(4y+20) =>  9y - 2y - 10, or 7y - 10.</span>
Leya [2.2K]4 years ago
6 0
An equivalent expression could just be one that is simplified. So we get 9y - 2y - 10 if we distribute the 1/2, which is 7y - 10.
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Hope this helps!
==jding713==
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Write in point-slope form an equation of the line that passes through the point (8, 9) with slope 7.
Lina20 [59]

Answer:

<h2>y=7x-47</h2>

Step-by-step explanation:

(8,9)=(x1,y1) \\ m=7 \\ y−y1=m(x−x1) \\ y−9=7(x−8)

y - 9 = 7x - 56 \\ y = 7x - 56 + 9 \\ y = 7x - 47

8 0
4 years ago
What is the length of line RS? Use the law of sines to find the answer.Round to the nearest tenth.
vitfil [10]
Refer to the diagram below.

Let x = length of line segment RS.
Let Q = ∠RQS.
Let S = ∠RSQ

According to the Law of Sines,
\frac{sinS}{2.4} = \frac{sin80^{o}}{3.1} \\\\sinS = (\frac{2.4}{3.1}) sin 80^{o}= 0.7624 \\\\ S = sin^{-1}0.7624 = 49.68^{o}

Because the sum of angles in a triangle is 180°, therefore
∠Q = 180 -(80 + 49.68) = 50.32°

Apply the Law of Sines again to obtain
\frac{x}{sinQ} = \frac{3.1}{sin80^{o}} \\\\ x = ( \frac{sin50.32^{o}}{sin80^{o}})3.1 =  2.423

Answer: The length of RS = 2.4 (nearest tenth)

5 0
3 years ago
Read 2 more answers
I need help with pythagoras’ theorem
fomenos

Answer:

Pythagoras’ theorem  is a way to find a side or hypothesis when you have 2 sides.  

The formula is:  a^2 + b^2 = c^2

a and b are sides

c is the hypothesis

<u>Ex:  A triangle has a leg that is 5 inches and a leg that is 7 inches.  Find the hypothesis using Pythagoras' theorem.  </u>

A leg is another way of saying a side.

5^2 + 7^2 = c^2

25 + 49 = x^2

sqrt(74) = sqrt(x^2)

sqrt(74) inches = hypothesis

<u>Ex:  A triangle has a leg that is 9 feet and a hypothesis that is 25 feet.  Find the other leg using Pythagoras' theorem. </u>

9^2 + b^2 = 25^2

81 + b^2 - 81 = 625 - 81

sqrt(b^2) = sqrt(544)

b = sqrt(554)

Do you understand more?

4 0
3 years ago
Find the projection of u onto v<br> URGENT HELP
padilas [110]

Given:

Two vectors are:

u=\left

v=\left

To find:

The projection of u onto v.

Solution:

Magnitude of a vector v=\left is:

|v|=\sqrt{a^2+b^2}

Dot product of two vector v_1=\left and v_2=\left is:

v_1\cdot v_2=a_1a_2+b_1b_2

Formula for projection of u onto v is:

Proj_vu=\dfrac{u\cdot v}{|v|^2}v

Proj_vu=\dfrac{\left \cdot \left }{(\sqrt{2^2+17^2)^2}}\left

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Proj_vu=\dfrac{0+102}{293}\left

On further simplification, we get

Proj_vu=\dfrac{102}{293}\left

Proj_vu=\left

Proj_vu=\left

Therefore, the projection of u onto v is Proj_vu=\left.

3 0
3 years ago
Difference of the square of (x+6)(x+4)
sweet-ann [11.9K]

Answer:

x^2 + 10x + 24

Step-by-step explanation:

(x+6)(x+4)

x^2 + 4x + 6x + 24

x^2 + 10x + 24

5 0
3 years ago
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