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3 years ago

13

describe a situation in which a formula could be used more easily if it were rearranged. Include the formula in your description

.

2 answers:

pshichka [43]3 years ago

5 0

I need to find the length of something when I am given the volume, width, and height.

v=lwh
l = v/wh

Hope this helps!

Anni [7]3 years ago

3 0

Distance,speed, time formula

d = s * t

if ur looking for time, re-arrange the formula so it reads t = d / s
if ur looking for speed, re-arrange the formula so it reads s = d / t

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35 POINTS AVAILABLE

aliina [53]

Answer:

Part 1) The length of each side of square AQUA is $3.54\ cm$

Part 2) The area of the shaded region is $(486\pi-648)\ units^{2}$

Step-by-step explanation:

Part 1)

<em>step 1</em>

Find the radius of the circle S

The area of the circle is equal to

$A=\pi r^{2}$

we have

$A=25\pi\ cm^{2}$

substitute in the formula and solve for r

$25\pi=\pi r^{2}$

simplify

$25=r^{2}$

$r=5\ cm$

<em>step 2</em>

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

$SU=r=5\ cm$

Let

x------> the length side of the square

Applying the Pythagoras Theorem

$5^{2}=x^{2} +x^{2}$

$5^{2}=2x^{2}$

$x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm$

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

<em>Find the area of the larger circle</em>

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=AB=18\ units$

substitute in the formula

$A=\pi (18)^{2}=324\pi\ units^{2}$

step 2

Find the length of each side of square BCDE

we have that

$AB=18\ units$

The diagonal DB is equal to

$DB=(2)18=36\ units$

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

$36^{2}=x^{2} +x^{2}$

$1,296=2x^{2}$

$648=x^{2}$

$x=\sqrt{648}\ units$

step 3

Find the area of the square BCDE

The area of the square is

$A=(\sqrt{648})^{2}=648\ units^{2}$

step 4

Find the area of the smaller circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=(\sqrt{648})/2\ units$

substitute in the formula

$A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}$

step 5

Find the area of the shaded region

$324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}$

7 0

3 years ago

Simplify this expression. (2-5sqrt6)*3sqrt2<br> Please hurry taking a test.

a_sh-v [17]

Answer:

D

Step-by-step explanation:

7 0

3 years ago

Hassan writes an algebraic expression with four terms. The x-term has a coefficient of 2 and the z-term has a coefficient of -1.

mixer [17]

Z(2/.0005)•Y maybe hope it helped

5 0

3 years ago

What is the IQR (interquartile range)?

Ivanshal [37]

Median..................

4 0

3 years ago

P is an odd number.<br> Explain why p^2 +1 is always even number

Stells [14]

Answer:

every odd number that squares up and add 2 will give an even answer

8 0

3 years ago

Read 2 more answers