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dedylja [7]
3 years ago
6

England and Canada have what cultural characteristic in common?A. A majority of the population in both is Roman Catholic.B A maj

ority of the population in both is illiterate.C. They both have a celebration of the Queen's Birthday.D. They both have 2 official main languages.
Social Studies
2 answers:
Sloan [31]3 years ago
7 0

Something both Canada and England have in common is that they C. Both have a celebration of the queen's Birthday.

likoan [24]3 years ago
7 0

C. They both have a celebration of the Queen's Birthday.

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At preschool, Jessi has learned that she must wash her hands before snack-time in order to get a snack. At home, she has started
KATRIN_1 [288]

Answer: stimulus generalization.

Explanation:

Stimulus generalization can happen in classical conditioning as well as in operant conditioning. When it´s in operant conditioning, stimulus generalization describes the way people learn something in a specific situation and then can apply it to different but similar circumstances.

In this example, Jessi first learned at preschool that to get a snack she has to wash her hands. Instead of having to relearn this practice at home, she applied the same rule she had already learned.

6 0
3 years ago
what groups of people does crevecoeur omit from his essay? how might their veiw of america be different
kati45 [8]

Crèvecoeur omits the many waffling people in the middle, who wanted to stay home on their farms rather than shed blood for either side

Explanation:

John de Crèvecoeur is French born American who had done many roles in his life term like he was farmer and very good writer. In his Letter from an American Farmer he narrated the life style of American in the period of 18th century. His narration is extremely based on the how America transformed from the old thoughts and how the people has accustomed to the various races of people settled over there. He was the keen observer of the revolution and narrated his thoughts in the “Letter from an American Farmer”. While do so he has omitted the waffling people of middle who were not involved themselves in the revolution rather they were do their farming activities.

5 0
3 years ago
Which part of an investogation is only found in an exirmental investigation
Alex777 [14]
A group used in a study or in an experiment, which does not get treatment by the scientists and is used as a foundation to determine the functions of the other tested subjects is known as the control group. The control group is only found in an experimental investigation.
6 0
2 years ago
What is similar about republics and constitutional monarchies ?
wariber [46]
Well, both of them have a head of government, both run off of constitutions, and often constitutional monarchies have elected officials similar to a republic.
6 0
3 years ago
Hens usually begin laying eggs when they are about 6 months old. Young hens tend to lay smaller​ eggs, often weighing less than
miv72 [106K]

Answer:

          \large\boxed{\large\boxed{1.33g}}

Explanation:

Your question has one part only: <em>a) The average weight of the eggs produced by the young hens is 50.1 ​grams, and only 25​% of their eggs exceed the desired minimum weight. If a Normal model is​ appropriate, what would the standard deviation of the egg weights​ be?</em>

<em />

<h2><em>Solution</em></h2><h2><em /></h2>

You are given the <em>mean</em>, the reference value, and the <em>percent of egss that exceeds that minimum</em>.

In terms of the parameters of a normal distribution that is:

  • <em>mean</em> =<em> 50.1g</em> (μ)
  • X<em> = 51 g</em>
  • Area of the graph above X = 51 g = <em>25%</em>

Using a standard<em> normal distribution</em> table, you can find the Z-score for which the area under the curve is greater than 25%, i.e. 0.25

The tables with two decimals for the Z-score show probability 0.2514 for Z-score of 0.67 and probabilidad 0.2483 for Z-score = 0.68.

Thus, you must interpolate. Since, (0.2514 + 0.2483)/2  ≈ 0.25, your Z-score is in the middle.

That is, Z-score = (0.67 + 0.68)/2 = 0.675.

Now use the formula for Z-score and solve for the <em>standard deviation</em> (σ):

          Z-score=(x-\mu)/\sigma

          0.675=(51g-50.1g)/\sigma

          \sigma =0.9g/0.675=1.33g

6 0
3 years ago
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