Answer: stimulus generalization.
Explanation:
Stimulus generalization can happen in classical conditioning as well as in operant conditioning. When it´s in operant conditioning, stimulus generalization describes the way people learn something in a specific situation and then can apply it to different but similar circumstances.
In this example, Jessi first learned at preschool that to get a snack she has to wash her hands. Instead of having to relearn this practice at home, she applied the same rule she had already learned.
Crèvecoeur omits the many waffling people in the middle, who wanted to stay home on their farms rather than shed blood for either side
Explanation:
John de Crèvecoeur is French born American who had done many roles in his life term like he was farmer and very good writer. In his Letter from an American Farmer he narrated the life style of American in the period of 18th century. His narration is extremely based on the how America transformed from the old thoughts and how the people has accustomed to the various races of people settled over there. He was the keen observer of the revolution and narrated his thoughts in the “Letter from an American Farmer”. While do so he has omitted the waffling people of middle who were not involved themselves in the revolution rather they were do their farming activities.
A group used in a study or in an experiment, which does not get treatment by the scientists and is used as a foundation to determine the functions of the other tested subjects is known as the control group. The control group is only found in an experimental investigation.
Well, both of them have a head of government, both run off of constitutions, and often constitutional monarchies have elected officials similar to a republic.
Answer:
Explanation:
Your question has one part only: <em>a) The average weight of the eggs produced by the young hens is 50.1 grams, and only 25% of their eggs exceed the desired minimum weight. If a Normal model is appropriate, what would the standard deviation of the egg weights be?</em>
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<h2><em>Solution</em></h2><h2><em /></h2>
You are given the <em>mean</em>, the reference value, and the <em>percent of egss that exceeds that minimum</em>.
In terms of the parameters of a normal distribution that is:
- <em>mean</em> =<em> 50.1g</em> (μ)
- Area of the graph above X = 51 g = <em>25%</em>
Using a standard<em> normal distribution</em> table, you can find the Z-score for which the area under the curve is greater than 25%, i.e. 0.25
The tables with two decimals for the Z-score show probability 0.2514 for Z-score of 0.67 and probabilidad 0.2483 for Z-score = 0.68.
Thus, you must interpolate. Since, (0.2514 + 0.2483)/2 ≈ 0.25, your Z-score is in the middle.
That is, Z-score = (0.67 + 0.68)/2 = 0.675.
Now use the formula for Z-score and solve for the <em>standard deviation</em> (σ):
