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Stels [109]
3 years ago
11

Renita analyzed two dot plots showing the snowfall during the winter months for City A and for City B. She found that the

Mathematics
2 answers:
kiruha [24]3 years ago
6 0

Answer:

The answer is "A"

Step-by-step explanation:

SCORPION-xisa [38]3 years ago
3 0

Answer:

A) One set of data has more variation than the other.

Step-by-step explanation:

<em> did the test</em>

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If f(x) = 3^x and g(x) = 3^(x+1)+6. Describe the transformations from f(x) to g(x).
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To move tot he right h units, subtract h from every x to move up k units, add k to the whole equaiton added 1 to every x (subtract -1) added6 to whole thing moved -1 to right (moved 1 to left) moved up 6 units answer is A
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Answer is b for this question
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2 years ago
Which of the following is the quotient of the rational expressions shown here? x/x-1 / 1/x 1.
WINSTONCH [101]

The quotient of the rational expressions is \rm \dfrac{x^2-x}{x-1}.

<h3>Given that</h3>

Rational Expression; \rm \dfrac{x}{x-1} ÷\rm \dfrac{1}{x+1}

<h3>We have to determine</h3>

Which of the following is the quotient of the rational expressions shown here?

<h3>According to the question</h3>

Rational Expression; \rm \dfrac{x}{x-1} ÷\rm \dfrac{1}{x+1}

Then,

The quotient of the rational expressions is,

\rm \dfrac{x}{x-1} ÷\rm \dfrac{1}{x+1}

\rm =\dfrac{x}{x-1} \times \dfrac{x+1}{1}\\&#10;\\ =\dfrac{x(x-1)}{x\times 1}\\&#10;\\&#10;=\dfrac{x^2-x}{x-1}

Hence, The quotient of the rational expressions is \rm \dfrac{x^2-x}{x-1}.

To know more about Division click the link given below.

brainly.com/question/26163188

7 0
2 years ago
Use the pythagorean theorem to prove that this point lies on the unit circle. Find csc(0) where 0=-120.
exis [7]

By applying Pythagorean theorem, we have proven that the point (-1/2, -√3/2) lies on the unit circle.

<h3>How to prove this point lies on the unit circle?</h3>

In Trigonometry, an angle with a magnitude of -120° is found in the third quarter and as such, both x and y would be negative. Also, we would calculate the reference angle for θ in third quarter as follows:

Reference angle = 180 - θ

Reference angle = 180 - 120

Reference angle = 60°.

For the coordinates, we have:

sin(-120) = -sin(60) = -1/2.

cos(-120) = -cos(60) = -√3/2.

By applying Pythagorean theorem, we have:

z² = x² + y²

z = √((-1/2)² + (-√3/2)²)

z = √(1/4 + 3/4)

z = √1

z = 1.

Read more on unit circle here: brainly.com/question/9797740

#SPJ1

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2 years ago
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