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levacccp [35]
3 years ago
12

A quadrilateral with vertices (-3,3), (-3,0), (3,0), and (3,3) is reflected across the y axis. which is not a vertex of the imag

e.
Mathematics
1 answer:
notka56 [123]3 years ago
4 0

The reflected coordinates are = (3,3) , (3,0) , (-3,0) , (-3,3)

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Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!​
Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

\frac{3}{x + 4}  - \frac{1}{x + 3}  = \frac{x + 9}{(x^2 + 7x + 12)}

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

\frac{3*(x + 4)}{x + 4}  - \frac{(x + 4)}{x + 3}  = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}

3  - \frac{(x + 4)}{x + 3}  = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}

Now we can multiply both sides by (x + 3)

3*(x + 3)  - \frac{(x + 4)*(x+3)}{x + 3}  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

3*(x + 3)  - (x + 4)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

(2*x + 5)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}

Now we can multiply both sides by (x^2 + 7*x + 12)

(2*x + 5)*(x^2 + 7x + 12)  = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)

(2*x + 5)*(x^2 + 7x + 12)  = (x + 9)*(x + 4)*(x+3)

Now we need to solve this:

we will get

2*x^3 + 19*x^2 + 59*x + 60 =  (x^2 + 13*x + 3)*(x + 3)

2*x^3 + 19*x^2 + 59*x + 60 =  x^3 + 16*x^2 + 42*x + 9

Then we get:

2*x^3 + 19*x^2 + 59*x + 60 - (  x^3 + 16*x^2 + 42*x + 9) = 0

x^3 + 3x^2 + 17*x + 51 = 0

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0
3 years ago
How do you do inequalitys?
nata0808 [166]
I think this quisthionbchk shjvsjjwv hsjvsbkzbxbs hhsvsvwjkwvs hskvsvdod
4 0
3 years ago
What is 3940 times 4869
r-ruslan [8.4K]

Answer:


Step-by-step explanation:

4869 x 3940 = 19183860

4 0
3 years ago
Read 2 more answers
A rectangle is 3 cm long and 2 cm wide
Nimfa-mama [501]

Answer:

Perimeter = 100mm

Area = 60mm

Step-by-step explanation:

P= (3x2) + (2x2) =10cm

10mm to 1cm

10cm x 10 = 100mm

A= b x h

= 3 x 2

=6cm

6x10=60mm

7 0
3 years ago
Evaluate the expression 4a^2 - 2b ÷ 4 for a = 2 and b = 4.
Alexxandr [17]
(4a² -2b)/4
(4(2)² - 2×4)/4
(16-8)/4
8/4
= 2


please don't forget to give my answer brainliest if they are correct
3 0
3 years ago
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