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3 years ago

Find the slope of the line.

Mathematics

2 answers:

Ainat [17]3 years ago

7 0

5/6 would be the slope of the line

rewona [7]3 years ago

3 0

Answer:

5/6

Step-by-step explanation:

Remember your rise over run!

2.5/3 = 5/6

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Which Data set has the smallest IQR ?

mel-nik [20]

Answer:

<h2 /><h2>The interquartile range (IQR) is the difference between the upper (Q3) and lower (Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest. The IQR is often seen as a better measure of spread than the range as it is not affected by outliers. Interquartile Range. 25% of values.</h2>

<h2 />

<h2>here your answer </h2>

8 0

3 years ago

Use substitution to solve the system of equations. Write your solution in decimal form

Lera25 [3.4K]

Answer:

(1.6, 7.02)

Step-by-step explanation:

5 more brainliest for expert : )

4 0

2 years ago

baherus [9]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = $\frac{\sqrt3}{2}$

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

$\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}$

Proof LHS → RHS:

LHS cos 165

Double-Angle: cos (2 · 165) = 2 cos² 165 - 1

⇒ cos 330 = 2 cos² 165 - 1

⇒ 2 cos² 165 = cos 330 + 1

Given: $2 \cos^2 165 = \dfrac{\sqrt3}{2} + 1$

$\rightarrow 2 \cos^2 165 = \dfrac{\sqrt3}{2} + \dfrac{2}{2}$

Divide by 2: $\cos^2 165 = \dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \dfrac{2\sqrt3+4}{8}$

Square root: $\sqrt{\cos^2 165} = \sqrt{\dfrac{4+2\sqrt3}{8}}$

Scratchwork: $\cos^2 165 = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2$

$\rightarrow \cos 165 = \pm \dfrac{\sqrt3+1}{2\sqrt2}$

Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

$\rightarrow \cos 165 = - \dfrac{\sqrt3+1}{2\sqrt2}$

LHS = RHS $\checkmark$

4 0

3 years ago

a line with slope 3 passes through point (0,10). What is the y-coordinate of the point on the line with x-coordinate 2

skad [1K]

The y-coordinate is 16

<h3><u>Solution:</u></h3>

Given that a line with slope 3 passes through point (0, 10)

To find the y-coordinate of the point on the line with x-coordinate 2

Which means the point is (2, y)

Let us find the required y co-ordinate using slope formula

<em><u>The slope of line is given as:</u></em>

For a line containing points $(x_1 , y_1)$ and $(x_2 , y_2)$ is given as:

$\text {slope}=m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text {Here } x_{1}=0 ; y_{1}=10 ; x_{2}=2 ; y_{2}=y$

Given that slope "m" = 3

Substituting the values we get,

$\begin{array}{l}{3=\frac{y-10}{2-0}} \\\\ {3=\frac{y-10}{2}} \\\\ {6=y-10} \\\\ {y=10+6=16}\end{array}$

Thus the y-coordinate is 16

8 0

3 years ago

Z=a/b+c/d solve for A

PilotLPTM [1.2K]

Answer: $a=\frac{b(zd-c)}{d}$

Step-by-step explanation:

Having the following equation given in the exercise:

$z=\frac{a}{b}+\frac{c}{d}$

You can solve for "a" following this procedure:

1. You can apply the Subtraction property of equality and subtract $\frac{c}{d}$ from both sides of the equation:

$z-(\frac{c}{d})=\frac{a}{b}+\frac{c}{d}-(\frac{c}{d})\\\\z-\frac{c}{d}=\frac{a}{b}$

2. Now you must subtract the terms on the left side of the equation. Notice that the Least Common Denominator is "d". Then:

$\frac{zd-c}{d}=\frac{a}{b}$

3. Finally, you can apply the Multiplication property of equality and multiply both sides of the equation by "b". So, you get:

$(b)(\frac{zd-c}{d})=(\frac{a}{b})(b)\\\\a=\frac{b(zd-c)}{d}$

6 0

3 years ago