Answer:
<h2 /><h2>The interquartile range (IQR) is the difference between the upper (Q3) and lower (Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest. The IQR is often seen as a better measure of spread than the range as it is not affected by outliers. Interquartile Range. 25% of values.</h2>
<h2 />
<h2>here your answer </h2>
Answer:
(1.6, 7.02)
Step-by-step explanation:
5 more brainliest for expert : )
Answer: see proof below
<u>Step-by-step explanation:</u>
Given: cos 330 = 
Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

Proof LHS → RHS:
LHS cos 165
Double-Angle: cos (2 · 165) = 2 cos² 165 - 1
⇒ cos 330 = 2 cos² 165 - 1
⇒ 2 cos² 165 = cos 330 + 1
Given: 

Divide by 2: 

Square root: 
Scratchwork: 

Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

LHS = RHS 
The y-coordinate is 16
<h3><u>Solution:</u></h3>
Given that a line with slope 3 passes through point (0, 10)
To find the y-coordinate of the point on the line with x-coordinate 2
Which means the point is (2, y)
Let us find the required y co-ordinate using slope formula
<em><u>The slope of line is given as:</u></em>
For a line containing points
and
is given as:


Given that slope "m" = 3
Substituting the values we get,

Thus the y-coordinate is 16
Answer: 
Step-by-step explanation:
Having the following equation given in the exercise:

You can solve for "a" following this procedure:
1. You can apply the Subtraction property of equality and subtract
from both sides of the equation:

2. Now you must subtract the terms on the left side of the equation. Notice that the Least Common Denominator is "d". Then:

3. Finally, you can apply the Multiplication property of equality and multiply both sides of the equation by "b". So, you get:
