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Licemer1 [7]
4 years ago
11

bart takes a random sample of 50 students in his seventh-grade class and finds that 40% of the sample prefers chocolate ice crea

m over vanilla ice cream. there are 200 students in the seventh grade. based on the sample proportion, about how many students in the seventh grade would be expected to prefer chocolate ice cream over vanilla ice cream? 40 80 50 200
Mathematics
2 answers:
elixir [45]4 years ago
8 0
80 students would prefer chocolate ice cream over vanilla. 50x.20=20 studentsx4=80 students
Aleks04 [339]4 years ago
8 0

Answer: Second option is correct.

Step-by-step explanation:

Since we have given that

In a sample of 50 students in seventh - grade class ,

Percentage of the sample prefers chocolate ice- cream over vanilla ice = 40%

So, In a sample of 200 students in the seventh - grade class,

Percentage of the sample prefers chocolate ice- cream over vanilla ice is also 40%.

So, Number of students in the seventh grade would be expected to prefer chocolate ice cream over vanilla ice cream is given by

\frac{40}{100}\times 200\\\\=40\times 2\\\\=80

Hence, there are 80 students in the seventh grade would be expected to prefer chocolate ice cream over vanilla ice cream.

Thus, Second option is correct.

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Answer:

x = -7 or  x = 1

Step-by-step explanation:

Given expression:

    (x + 3)²  = -16

 

Problem;

   Solve for x;

Solution:

 To solve for x; we use the factorization method;

     Take -16 to the left of the equation;

      (x + 3)²  = -16

         (x + 3)² + 16 = 0

       (x+ 3)² + 4²  = 0

if    x² + y²  = (x + y)(x - y)

     So;

       (x + 3 + 4) (x + 3 - 4) = 0

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       x + 7  = 0 or x - 1 = 0

      x = -7 or  x = 1

6 0
3 years ago
In the figure below, YZA and YZX are right angles, XYZ and AYZ are congruent, and XZ = 10. What is the length of ?
lilavasa [31]

Answer:

  C.  10

Step-by-step explanation:

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3 0
3 years ago
Dogs are inbred for such desirable characteristics as blue eye color, but an unfortunate by-product of such inbreeding can be th
sesenic [268]

Answer:

The probability that the dogs are blue eyed and deaf is 13.02%.

Step-by-step explanation:

We are given the following information in the question:

P(Blue eyes) = 31%

P(Deaf) = 38%

P(Deaf | Blue eyes) = 42%

Formula for conditional probability:

P( A|B) = \displaystyle\frac{P(A \cap B)}{P(B)}

Now, let A be the event where the dog is deaf and B be the the event where dog is blue eyed.

P( \text{ Deaf}|\text{Blue eyes}) = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{P(\text{Blue eyes})}\\\\0.42 = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{0.31}\\\\P( \text{Deaf} \cap \text{Blue eyes}) = 0.42\times 0.31 = 0.1302 = 13.02\%

Hence, the probability that the dogs are blue eyed and deaf is 13.02%.

6 0
3 years ago
In the triangles below, what value of x would make the triangles similar?
Flauer [41]

Answer: 15

Step-by-step explanation:

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3 0
3 years ago
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