Question

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Answer 1

The first polynomial is completely factored; the numbers 121 and 36 don't have a common factor,  and  the variables are different, so you can't factor them either.
The other three can still be factored:
$(4x+4)(x+1)=4(x+1)(x+1)=4(x+1)^{2}$
$2x( x^{2} -4)=2x(x+2)(x-2)$
$3 x^{4} -15 n^{3} +12n^{2} =3 x^{4} -n^{2} (15n-12)$

The correct answer is the first one.