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3 years ago

Helpppppppppppppppppppppppppppp

Mathematics

1 answer:

Leto [7]3 years ago

4 0

The first polynomial is completely factored; the numbers 121 and 36 don't have a common factor, and the variables are different, so you can't factor them either.
The other three can still be factored:
$(4x+4)(x+1)=4(x+1)(x+1)=4(x+1)^{2}$
$2x( x^{2} -4)=2x(x+2)(x-2)$
$3 x^{4} -15 n^{3} +12n^{2} =3 x^{4} -n^{2} (15n-12)$

The correct answer is the first one.

You might be interested in

Are 22/32 equivalent to 11/16

Allisa [31]

Answer:

Yes!

Step-by-step explanation:

22/32 divided by 2 equals 11/16, meaning they are equivalent.

7 0

3 years ago

At Elisa's printing company, there are two kinds of printing presses: Model A, which can print 70 books/ day, and model B, which

Dmitrij [34]

Answer:

9 Model As.

Step-by-step explanation:

Let A represent Press A and let B represent Press B.

So, they own 14 total presses. This means that:

$A+B=14$

They can print 905 books per day, in other words, since A prints 70 per day and B prints 55 per day:

$70A+55B=905$

This is now a system of equations. Solve by substitution. From the first equation, subtract B from both sides:

$A=14-B$

Substitute this into the second equation: "

$70(14-B)+55B=905$

First, we can divide everything by 5 to simplify things:

$14(14-B)+11B=181$

Distribute the left:

$196-14B+11B=181$

Combine like terms:

$-3B+196=181$

Subtract 196 from both sides:

$-3B=-15$

Divide both sides by -3

$B=5$

So, the company has 5 Model B presses.

Which means that the company has 14-5 or 9 Model A presses.

And we're done!

3 0

3 years ago

In a genetics experiment on peas, one sample of offspring contained green peas and yellow peas. Based on those results, estimate

dem82 [27]

Complete Question

In a genetic experiment on peas, one sample of offspring contained 436 green peas and 171 yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3/4 that was expected? The probability of getting a green pea is approximately: Is the probability reasonably close to 3/4?

Answer:

The probability is $P(g) =0.72$

Yes the result is reasonably close

Step-by-step explanation:

From the question we are told that

The number of of green peas is $g = 436$

The number of yellow peas is $y = 171$

The sample size is $n = 171 + 436 = 607$

The probability of getting an offspring pea that is green is mathematically represented as

$P(g) = \frac{g}{n}$

$P(g) = \frac{436}{607}$

$P(g) =0.72$

Comparing $P(g) =0.72$ to $\frac{3}{4} = 0.75$ we see that the result is reasonably close

7 0

4 years ago

Please show your work, I'd really appreciate the help! :)

xenn [34]

Y=12.5+1.25X , this is how youget the fair admission amount 43.75-(25x1.25)=12.5

3 0

3 years ago

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. Only 1 try

vagabundo [1.1K]

Using the shell method, the volume is

$\displaystyle 2\pi \int_0^1 (2-x) \cdot 8x^3 \, dx = 16\pi \int_0^1 (2x^3 - x^4) \, dx$

Each cylindrical shell has radius $2-x$ (the horizontal distance from the axis of revolution to the curve $y=8x^3$ ); has height $8x^3$ (the vertical distance between a point on the $x$ -axis in $0\le x\le1$ and the curve $y=8x^3$ ).

Compute the integral.

$\displaystyle 16 \pi \int_0^1 (2x^3 - x^4) \, dx = 16\pi \left(\frac{x^4}2 - \frac{x^5}5\right) \bigg|_{x=0}^{x=1} \\\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = 16\pi \left(\frac12 - \frac15\right) \\\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = \frac{24}5\pi = \boxed{4.8\pi}$

6 0

2 years ago