B=number of ticets sold before
a=number of tickets sold after
cost of a ticket=number of tickets times cost per ticket
beforecost=39.95b
aftercost=54.95a
total cost=925000
39.95b+54.95a=925000
total number tickets=20000
b+a=20000
we have
39.95b+54.95a=925000
b+a=20000
multiply second equation by -39.95 and add to first equatin
39.95b+54.95a=925000
<u>-39.95b-39.95a=-799000 +</u>
0b+15a=126000
15a=126000
divide bot sides by 15
a=8400
sub back
b+a=20000
b+8400=20000
minus 8400 both sides
b=11600
11,600 tickets sold before
8400 tickets sold after
Answer: a
Step-by-step explanation:
Answer:
x= (y-5)/2
Step-by-step explanation:
Isolate the x variable.
y= 2x +5
Subtract 5 from both sides.
y-5=2x
Divide both sides by 2.
(y-5)/2= x
Answer:
Y= -12
Step-by-step explanation:
6(y + 7) = 2(y - 3)
6y+42=2y-6
4y+42=-6
4y=-48
y=-12
Yes there’s 44 remainders :)