The zeros for this function are -2, -1 and a double root of 0.
You can find this by first factoring the polynomial on the inside of the parenthesis. Polynomials like this can be factored by looking for two numbers that multiply to the constant (2) and add up to the second coefficient (3). The numbers 2 and 1 satisfy both of those needs and thus can be used as the numbers in a factoring.
x^2(x^2 + 3x + 2)
x^2(x + 2)(x + 1)
Now to find the zeros, we set each part equal to 0. You may want to split the x^2 into two separate x's for this purpose.
(x)(x)(x + 2)(x + 1)
x = 0
x = 0
x + 2 = 0
x = -2
x + 1 = 0
x = -1
Answer:
8
Steps:
Plug in 2 for x in h(x)
h(2) = -(2)^2 + 6 * 2
h(2) = -4 + 12
h(2) = 8
Answer:
a) 
Step-by-step explanation:
Step-by-step explanation:
I hope it helped and it is easy to understand i hope it was helpful
Answer:
Top one
Step-by-step explanation:
