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mezya [45]
3 years ago
13

Which expression is equivalent to Two-thirds x minus one-half y minus four-fifths? One-third x minus one-fourth y minus four-fif

ths + one-third x + one-fourth y One-third x minus one-fourth y minus four-fifths + one-third x minus one-fourth y One-third x minus one-fourth y minus one-fifth minus one-third x minus three-fifths minus one-fourth y One-third x minus one-fourth y + two-fifths + one-third x minus two-fifths minus one-fourth y
Mathematics
2 answers:
babymother [125]3 years ago
8 0

Answer:

The correct answer is B or

One-third x minus one-fourth y minus four-fifths + one-third x minus one-fourth y

Step-by-step explanation:

I just took the test

myrzilka [38]3 years ago
5 0

Answer:

It's B aka -2x - 3.

Step-by-step explanation:

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The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent. The two reductions together a
pantera1 [17]
It should be 40 percent.

You can think of it as starting with 100 as in 100 dollars or 100 tic tacs

If you take away 25%, you take away 25 tic tacs and now you only have 75.

From your 75, you take away 20% which is equal to 15. 75- 15=60

If you look at the end result of 60, you can see that that is 100 - 40 so 40% of the total was taken off
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Bella is wrapping a cube-shaped gift box that measures 8.5 inches along each edge. How many square inches of wrapping paper is n
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Answer:

433.5 in²

Step-by-step explanation:

A cube has 6 sides

Area of 1 side = 8.5 x 8.5 = 72.25 in²

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3 years ago
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Mary is buying several items that cost $128.25 total. She is using a store coupon for 35% off her purchases. She has to pay 4% s
scZoUnD [109]
If it is 35% off, then u r paying 65%...
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3 0
3 years ago
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The expression 3×150 is equivalent to
damaskus [11]

Answer:

450

Step-by-step explanation:

7 0
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Composition of functions Find g (f(x)) for the following problems
beks73 [17]

1.

f(x)=-3x\qquad g(x)=5x-6\\\\g(f(x))=5(-3x)-6=\boxed{-15x-6}

2.

f(x)=x-6\qquad g(x)=x^2+6x-2\\\\g(f(x))=(x-6)^2+6(x-6)-2=x^2-12x+36+6x-36-2=\\\\=\boxed{x^2-6x-2}

3.

f(x)=4x+3\qquad g(x)=2x^2-x+1\\\\g(f(x))=2(4x+3)^2-(4x+3)+1=2(16x^2+24x+9)-4x-3+1=\\\\=32x^2+48x+18-4x-3+1=\boxed{32x^2+44x+16}

4.

f(x)=2x^2\qquad g(x)=8x^2+3x\\\\g(f(x))=8(2x^2)^2+3(2x^2)=8\cdot4x^4+6x^2=\boxed{32x^4+6x^2}

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