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3 years ago

Convert 40.39° to degrees, minutes, and seconds.

1 answer:

kramer3 years ago

6 0

The degrees stay the same.

Multiply the decimal by 60
0.39 x 60 = 23.4

Now take the decimal bit and mulitply by 60 to get the seconds.
0.4 x 60 = 24.

So the answer is: 40 degrees, 23 minutes, 24 seconds.

You might be interested in

Solve this system of equations by using substitution 3x + 5y = 23 y= x + 3

Iteru [2.4K]

Answer:

x=1

y=4

(1,4)

Step-by-step explanation:

TO SOLVE FOR X:

1. Substitute y=x+3 into the equation. This should look like this:

3x+5(x+3)=23

2. Use the distributive property.

3x+5x+15=23

3. Simplify:

8x+15=23

4. Subtract 15 from both sides. It should now lool like this:

8x=8

5. Divide both sides by 8.

x=1

TO SOLVE FOR Y:

1. Take x and substitute into original statement:

3(1)+5y=23

2. Simplify:

3+5y=23

3. Subtract 3 from both sides:

5y=20

4: Simplify:

y=4

CHECK ANSWER:

y=x+3

1. Substitute your answers

4=1+3

2. Simplify

4=4

3. Check for Truth. Is 4=4?

Yes. So your final answer is:

x=1

y=4

(1,4)

6 0

3 years ago

What is the circumference of a QUATER CIRCLE if the radius of the quater circle is 2CM

MissTica

To find the area of a quarter circle, you simply take a quarter of a full circle. As all quarters are equal, this means that the formula would be πr24πr24. But wait, there's more. If you notice, πr24=πr22πr24=πr22. This coincides with the circle formula, just with half the radius. Notice anything? A quarter of a circle can be calculated in the same way a circle a quarter the size can. This means that a quarter circle is equal to a circle a quarter size. In this same way, a ninth of a circle is equal to a circle of one ninth the size.

8 0

3 years ago

PLEASE HELP! THiS IS DUE!!!!!!!! I Will MAKE BRAINlST

9966 [12]

Answer:

$\mathrm{26.\qua\:H\quad\:2 \dfrac{ 1 }{ 4 }\qua\:mi}$

$\mathrm{27.\qua\:D\quad\: 9\dfrac{ 1 }{ 8 }\qua\:lb}$

$\mathrm{28.\qua\:H\quad\:14.6}$

$\mathrm{29.\qua\:C\quad\:25\%}$

$\mathrm{30.\qua\:J\quad\:33.912\qua\ ft^{3} }$

Step-by-step explanation:

26.

$\mathrm{\dfrac{ 3 }{ 4 }\:mile\:per\:one\:hour}$

$\mathrm{To\:find\:how\:far\:Jet's\:cousin\:can\:walk\:in\:3\:hours\:,\:we\:multiply\:\dfrac{ 3 }{ 4 }\:by\:3}$

$3 \times \dfrac{ 3 }{ 4 }$

$\mathrm{Express\: 3 \times \left( \dfrac{ 3 }{ 4 } \right)\:as\:a\:singe\:fraction}$

$\dfrac{ 3 \times 3 }{ 4 }$

$\mathrm{Multiply\:3\:and\:3\:to\:get\:9}$

$\dfrac{ 9 }{ 4 }$

$\mathrm{Convert\:\dfrac{ 9 }{ 4 }\:to\:a\:mixed\:number}$

$2 \dfrac{ 1 }{ 4 }$

$\mathrm{So\:she\:can\:walk\:2 \dfrac{ 1 }{ 4 }\:miles\:in\:3\:hours}$

27.

$\mathrm{Since\:we\:want\:to\:find\:how\:many\:pounds\:both\:pumpkins\:weigh\:together,\:we\:have\:to\:add.}$

$5 \dfrac{ 3 }{ 4 } +3 \dfrac{ 3 }{ 8 }$

$\mathrm{Turn\:both\:mixed\:fractions\:into\:improper\:fractions}$

$\dfrac{ 23 }{ 4 } + \dfrac{ 27 }{ 8 }$

$\mathrm{Least\:common\:multiple\:of\:4\:and\:8\:is\:8}$

$\mathrm{Multiples\:of\:4}:\quad4,8,12,16,20$

$\mathrm{Multiples\:of\:8}:\quad8,16,24,32,40$

$\dfrac{ 23 }{ 4 } + \dfrac{ 27 }{ 8 }$

$\mathrm{Convert\: \dfrac{ 23 }{ 4 } \:and\: \dfrac{ 27 }{ 8 } \:to\:fractions\:with\:denominator\:8}$

$\dfrac{ 23 \times 2 }{ 4 \times 2 } + \dfrac{ 27 }{ 8 }$

$\mathrm{Simplify}$

$\dfrac{ 46 }{ 8 } + \dfrac{ 27 }{ 8 }$

$\mathrm{Since\: \dfrac{ 46 }{ 8 }\:and\:\dfrac{ 27 }{ 8 }\:have\:the\:same\:denominators,\:add\:them\:by\:adding\:their\:numerators}$

$\dfrac{ 46+27 }{ 8 }$

$\mathrm{Add\:46\:and\:27\:to\:get\:73}$

$\dfrac{ 73 }{ 8 }$

$\mathrm{Convert\:\dfrac{ 73 }{ 8 }\:to\:a\:mixed\:number}$

$9 \dfrac{ 1 }{ 8 }$

$\mathrm{Both\:pumpkins\:weighed\:9 \dfrac{ 1 }{ 8 }\:pounds\:all\:together}$

28.

Since the question is asking us "How many more miles did Alyce travel than Jason", we have to subtract the miles Jason traveled from the miles Alyce traveled.

$29.193-14.593$