Answer:
Hope fully this montage helps.
Step-by-step explanation:
Sn=n/2 (2a1 +(n-1)d)
[s5= 5/2 (2a1 +(5-1)d) = 5a1+10d]
s6=3(2a1+5d) = 6a1+15d
s4=2(2a1+3d) = 4a1+6d
6a1+15d -(4a1+6d) = 5 -----(1)
s7=7/2(2a1+6d) =7a1+21d
6a1+15d + 7a1+21d = 21 -----(2)
(1) 2a1+9d=5 -----(3)
(2) 13a1+36d=21 ----(4)
(3)*4 ; 8a1+36d=20 ----(5)
(4)-(5) 5a1 = 1
so a1 = 1/5
(3) 2a1+9d=5
2(1/5)+9d = 5
9d = 5-2/5 =23/5
d = 23/45
so [s5= 5/2 (2a1 +(5-1)d) = 5a1+10d = 5(1/5) + 10(23/45) = 1 + 5.11 = 6.11 ]
i'm not sure about the answer but the process is correct
Answer:
Only II. is written in standard form
Step-by-step explanation:
The three polynomials given are:
I. 
II. 
III. 
A polynomial is said to be in standard form when the variables are written in terms of descending powers i.e. the term with the highest power first, followed by the next and so on.
Examining the three polynomials I, II and III, there is only one which follows this rule and that is:
II. 
The term with the highest power (3) came first, followed by the term with the next degree of power (1) and the last term with degree of power as 0.
Hence, only II. is written in standard form.
There could have been 31 people at the game. Or there could have been 13 million 642 thousand 837 of them. There are a lot of other possibilities too. Can you find some more without help ?
Answer:
The answer should be 9in.
hope that helped.
Step-by-step explanation: