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Oksi-84 [34.3K]
3 years ago
6

Plz solve itFactorize: no w​

Mathematics
1 answer:
saul85 [17]3 years ago
3 0

Answer:

here we can go for two solution

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A farmer is building a fence to enclose a rectangular area consisting of two separate regions. The four walls and one additional
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  58.5 ft by 39 ft

Step-by-step explanation:

Let x represent the length of the two horizontal segments. Then the three vertical segments will be ...

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The total enclosed area is the product of these dimensions:

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This is the equation of a downward-opening parabola with zeros at x=0 and x=117. The maximum of the parabola will be on the line of symmetry, halfway between these zeros. The value of x there is ...

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The lengths of the vertical segments are ...

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The dimensions of the region enclosing the maximum area are 58.5 ft by 39 ft. The additional vertical segment is 39 ft.

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<em>Comment on maximum area problems</em>

You may have noticed that the total length of the fence allocated to the long sides (2×58.5 = 117) is half the total length of fence and is equal to the total length of fence allocated to the short sides (3×39 = 117).

This relationship is true in all rectangular fencing problems where the area is being maximized for a given total fence length. It doesn't matter how many partitions there are in either direction: <em>the total of horizontal lengths is equal to the total of vertical lengths</em>.

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