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3 years ago

How do i calculate the percentage difference between two numbers????

Mathematics

1 answer:

lawyer [7]3 years ago

8 0

When finding the percent difference between two numbers, there are two ways you can do this.

1. The first way is how to calculate the percentage INCREASE of two numbers:

-The formula is Increase / Original Number × 100 = % increase

Step 1: Find out the difference between the two numbers you're comparing. New number - Original number = Increase.

Step 2: Divide the increase by the original number and then multiply your answer by 100. (If your answer is a negative number, then it is a percent decrease, not a percent increase.)

2. The second way is how to calculate the percentage DECREASE of two numbers:

Step 1: Find out the difference between the two numbers you're comparing. Original number - New number = Decrease.

Step 2: Divide the decrease by the original number and then multiply your answer by 100. Decrease ÷ Original Number × 100 = % Decrease. (If your answer is a negative number, then is is a percent increase, not a percent decrease.)

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bogdanovich [222]

4 triangles and 1 rectangle

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3 years ago

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Find f(2) and f(a+h) when f(x)=3x^2+2x+4

wolverine [178]

F(2) = 3(2)^2 + 2(2) + 4

= 3(4) + 4 + 4

= 12 + 8

f(2) = 20

f(a+h) = 3(a+h)^2 + 2(a+h) + 4

= 3(a^2 + 2ah + h^2) + 2a + 2h + 4

f(a+h) = 3a^2 + 6ah + 3h^2 + 2a + 2h + 4

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3 years ago

An ostrich run 6 mile in12 minut how far he could come in 40 minutes

bogdanovich [222]

The ostrich can run 20 miles in 40 minutes.

<u>Solution:</u>

Given that, An ostrich run 6 mile in 12 minutes

We have to find how far he could come in 40 minutes

Now, according to the given information

Ostrich runs 6 miles ⇒ 12 minutes

Then, “n” miles ⇒ 40 minutes

Now, by criss cross multiplication we get,

$\begin{array}{l}{\rightarrow 6 \times 40=n \times 12} \\\\ {\rightarrow 40=n \times 2} \\\\ {\rightarrow n=20}\end{array}$

Hence, the ostrich can run 20 miles in 40 minutes

8 0

3 years ago

John and Martha are contemplating having children, but John’s brother has galactosemia (an autosomal recessive disease) and Mart

Rina8888 [55]

<h2>Answer:</h2>

$Probability=\frac{1}{24}$

<h2>Step-by-step explanation:</h2>

As the question states,

John's brother has Galactosemia which states that his parents were both the carriers.

Therefore, the chances for the John to have the disease is = 2/3

Now,

Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.

Now, one of those children married with a person.

So,

Probability for the child to have disease will be = 1/2

Now, again the child's child (Martha) probability for having the disease is = 1/2.

Therefore,

<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

$Probability=\frac{2}{3}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{4}\\Probability=\frac{1}{24}$

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)

<em><u>Hence, the probability for the first child to have Galactosemia is $\frac{1}{24}$ </u></em>

3 0

3 years ago

50r − 6 = 82r − 70.<br> a. r=64<br> b. r= -64<br> c.r=2<br> d.r=-2

lisabon 2012 [21]

Answer:

Step-by-step explanation:

Hope this helps.

3 0

4 years ago